NEET Questions Solved


Two spherical conductors B and C having equal radii and carrying equal charges in them repel each other with a force F when kept apart at some distance. A third spherical conductor having same radius as that of B but uncharged is brought in contact with B, then brought in contact with C and finally removed away from both. The new force of repulsion between B and C is 

(1) F/4

(2) 3 F/4

(3) F/8

(4) 3 F/8

(4) Initially F=k.Q2r2 (fig. A). Finally when a third spherical conductor comes in contact alternately with B and C then removed, so charges on B and C are Q / 2 and 3Q / 4 respectively (fig. B)

Now force F'=k.Q23Q4r2=38F

Difficulty Level:

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