In which of the following reactions, standard reaction entropy changes (S°) is positive

and standard Gibbs energy change (G°) decreases sharply with increasing

temperature?

1. C(graphite) + 1/2 O2(g) CO(g)

2. CO(g) + 1/2 O2(g)CO2(g)

3. Mg(s) + 1/2 O2(g) MgO(s)

4. 1/2 C (graphite) + 1/2 O2(g) 1/2 CO2(g)

Subtopic:  Gibbs Energy Change |
 68%
From NCERT
NEET - 2012
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The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0 °C is:

1. 10.52 cal/(mol K)

2. 21.04 cal/(mol K)

3. 5.260 cal/(mol K)

4. 0.526 cal/(mol K)

Subtopic:  Enthalpy & Internal energy |
 80%
From NCERT
NEET - 2012
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The standard enthalpy of vaporisation vapH° for water at 100°C is 40.66 kJ mol-1. The

internal energy of vaporisation of water at 100°C (in kJ mol-1) is- 

(Assume water vapour to behave like an ideal gas)

1. +37.56                   

2. -43.76

3. +43.76                   

4. +40.66

Subtopic:  Enthalpy & Internal energy |
 59%
From NCERT
NEET - 2012
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If the enthalpy change for the transition of liquid water to steam is 30 kJ mol-1 at 27°C,

the entropy change for the process would be

1. 1.0 J mol-1 K-1

2. 0.1 J mol-1K-1

3. 100 J mol-1K-1

4. 10 J mol-1K-1

Subtopic:  Enthalpy & Internal energy |
 80%
From NCERT
NEET - 2011
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Which of the following options correctly describes the free expansion of an ideal gas under adiabatic conditions?
1. \(\mathrm{{q} \neq 0, ~~ \Delta {T}=0, ~~ {~W}=0} \)
2. \(\mathrm{{q}=0, ~~ \Delta {T}=0, ~~ {~W}=0} \)
3. \(\mathrm{{q}=0, ~~ \Delta {T}<0, ~~ {~W} \neq 0} \)
4. \(\mathrm{{q}=0, ~~ \Delta {T} \neq 0, ~~ {~W}=0} \)

Subtopic:  Thermodynamics' Properties and process |
 69%
From NCERT
NEET - 2011
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Enthalpy change for the reaction,

 4H(g) 2H2(g) is -869.6 kJ

The dissociation energy of H-H bond is

1. -869.6 kJ                 

2. + 434.8 kJ

3. +217.4 kJ                 

4. -434.8 kJ

Subtopic:  Thermochemistry |
 64%
From NCERT
NEET - 2011
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Standard entropies of X2, Y2 and XY3 are 60, 40 and 50 J K-1mol-1 respectively. For the reaction

12X2 + 32Y2           XY3; H =-30 kJ, 
to be at equilibrium, the temperature should be 
1. 750K
2. 1000K
3. 1250K
4. 500K

Subtopic:  Spontaneity & Entropy |
 76%
From NCERT
NEET - 2010
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Given the following bond energies:

H-H bond energy 431.37 kJ mol-1
C=C bond energy 606.10 kJ mol-1
C-C bond energy 336.49 kJ mol-1
C-H bond energy 410.50 kJ mol-1

Based on the data given above, enthalpy change for the following reaction will be:
 

1. 1523.6 kJ mol-1

2. -243.6 kJ mol-1

3. -120.0 kJ mol-1

4. 553.0 kJ mol-1

Subtopic:  Hess's Law |
 71%
From NCERT
NEET - 2009
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The values of H and S for the given reaction are 170 kJ and 170 JK–1, respectively.
\(\mathrm{C} \text { (graphite) }+\mathrm{CO}_2(\mathrm{~g}) \rightarrow 2 \mathrm{CO}(\mathrm{g})\)
This reaction will be spontaneous at:

1. 710 K

2. 910 K

3. 1110 K

4. 510 K

Subtopic:  Gibbs Energy Change |
 85%
From NCERT
NEET - 2009
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On the basis of the following E° values, the strongest oxidising agent is

[Fe(CN)6]4- [Fe(CN)6]3- + e-         E° = -0.35 V

 Fe2+ Fe3+ + e-; E° = -0.77 V

1. [Fe(CN)6]4-           

2. Fe2+

3. Fe3+                     

4. [Fe(CN)6]3-

Subtopic:  Electrode & Electrode Potential |
NEET - 2008
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