The correct statement regarding the basicity of arylamines is

(1) Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring p-electron system.

(2) Arylamines are generally more basic than alkylamines because of aryl group.

(3) Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridized

(4) Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring p-electron system.

Which of the following will be most stable diazonium salt $R{\mathrm{N}}_2^{+}{X}^{-}$ ?

1. ${\mathrm{CH}}_3{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

2. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

4. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{X}^{-}$

Which of the following is more basic than aniline?

1. Diphenylamine

2. Triphenylamine

3. p-Nitroaniline

4. Benzylamine

A given nitrogen-containing aromatic compound a reacts with Sn/HCl, followed by HNO₂ to give an unsatable compound B.B, on treament with phenol, forms a beautiful coloured compound C with the molecular formula C₁₂H₁₀N₂O. The structure of compound A is

Which one of the following nitro-compounds does not react with nitrous acid?

A reaction that can convert acetamide to methanamine is:

1. Carbylamine reaction

2. Hoffmann bromamide reaction

3. Stephens reaction

4. Gabriels phthalimide synthesis

In the chemical reactions,

the compounds 'A' and 'B', respectively, are:

1. Nitrobenzene and chlorobenzene

2. Nitrobenzene and fluorobenzene

3. Phenol and benzene

4. Benzene diazonium chloride and fluorobenzene

The product obtained on nitration followed by alkaline hydrolysis of acetylated aniline is:

1. o-Nitroacetanilide

2. o- and p-Nitroaniline

3. m-Nitroaniline

4. Acetanilide

In the compound given below,

the correct order of acidic nature of the positions (X), (Y) and (Z) is: 

(1) Z>X>Y

(2) X>Y>Z

(3) X>Z>Y

(4) Y>X>Z

ln the reaction, 

The product is: 

1. 

2. 

3. 

4.