m-chlorobenzaldehyde on reaction with conc. KOH at room temperature gives:

1. potassium m-chlorobenzoate and m-hydroxybenzaldehyde

2. m-hydroxybenzaldehyde and m-chlorobenzyl alcohol

3. m-chlorobenzyl alcohol and m-hydroxy benzyl alcohol

4. potassium m-chlorobenzoate and m-chlorobenzyl alcohol

Formylchloride has not been prepared so far. Which can function as formylchloride in formylation ?

(1) HCHO + HCl

(2) HCOOCH₃ + HCl

(3) CO + HCl

(4) HCONH₂ + HCl

In the reaction, the compound 'X' is:

(1) ${\mathrm{CH}}_3\mathrm{COOH}$

(2) $\mathrm{Br}·{\mathrm{CH}}_2\mathrm{COOH}$

(3) $({\mathrm{CH}}_3\mathrm{CO}{)}_2\mathrm{O}$

(4) $\mathrm{CHO}·\mathrm{COOH}$

The major product H of the given reaction sequence is:

CH₃-CH₂-CO-CH₃$\stackrel{{}_{-}\mathrm{CN}}{\to }$G$\underset{\mathrm{Heat}}{\overset{95<mspace\; width="1em"></mspace>\%<mspace\; width="1em"></mspace>{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }}$H

1. ${\mathrm{CH}}_3-\mathrm{CH}=\underset{|}{\mathrm{C}}-\mathrm{COOH}$
$<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>{\mathrm{CH}}_3$

2. ${\mathrm{CH}}_3-\mathrm{CH}=\underset{|}{\mathrm{C}}-\mathrm{CN}$
$<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>{\mathrm{CH}}_3$

3. $<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>\mathrm{OH}$
${\mathrm{CH}}_3-\mathrm{CH}-\underset{\left|}{\overset{\right|}{\mathrm{C}}}-\mathrm{COOH}$
$<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>{\mathrm{CH}}_3$

4. ${\mathrm{CH}}_3-\mathrm{CH}=\underset{|}{\mathrm{C}}-\mathrm{CO}-{\mathrm{NH}}_2$
$<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>{\mathrm{CH}}_3$

In presence of iodine catalyst, chlorine reacts with acetic acid to form:

1.
2.
3.
4.
 

Acetic acid is obtained when:

(1) glycerol is heated with sulphuric acid

(2) methyl alcohol is oxidized with potassium permanganate

(3) acetaldehyde is oxidized with potassium dichromate and sulphuric acid

(4) calcium acetate is distilled in presence of calcium formate

Main product of the reaction, 

CH₃CONH₂+HNO₂ $\to$... is:

(1) CH₃COOH

(2) CH₃CH₂NH₂

(3) CH₃NH₂

(4) CH₃COONH₄

The $-$COOH group in a carboxylic acid can be replaced by 'H' by heating the acid with:

(1) Zn with HCl

(2) H₂ in presence of nickel

(3) sodalime

(4) bromine and concentrated aqueous alkali

One mole of Grignard reagent reacts with the acid chlorides to give

1. Esters

2. Ethers

3. Ketone

4. None of the above

Amides can be converted into amines by:

1. Perkin reaction

2. Claisen reaction

3. Hofmann reaction

4. Kekule reaction