# NEET Questions Solved

A potentiometer is used for the comparison of e.m.f. of two cells E1 and E2. For cell E1 the no deflection point is obtained at 20cm and for E2 the no deflection point is obtained at 30cm. The ratio of their e.m.f.'s will be

(1) 2/3

(2) 1/2

(3) 1

(4) 2

(1) Ratio will be equal to the ratio of no deflection lengths i.e. $\frac{{E}_{1}}{{E}_{2}}=\frac{{l}_{1}}{{l}_{2}}=\frac{2}{3}$

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