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Q. No.Consider the given two statements:
Assertion (A):
It is possible to make calculations of the net gain of ATP for every glucose molecule oxidised; but in reality this can remain only a theoretical exercise.
Reason (R):
These calculations can be made only on certain assumptions that are not really valid in a living system.
1.
Both (A) and (R) are True and (R) correctly explains the (A)
2.
Both (A) and (R) are True but (R) is not the correct explanation of the (A)
3.
(A) is True but (R) is False
4.
(A) is False but (R) is True
Subtopic: Aerobic Respiration | THE RESPIRATORY BALANCE SHEET |
88%
Level 1: 80%+
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There can be a net gain of ____ ATP molecules during aerobic respiration of one molecule of glucose
[as per NCERT textbook]:
1. 30
2. 36
3. 38
4. 40
[as per NCERT textbook]:
1. 30
2. 36
3. 38
4. 40
Subtopic: THE RESPIRATORY BALANCE SHEET |
86%
Level 1: 80%+
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Consider the given two statements:
| Assertion (A): | It is better to consider the respiratory pathway as an amphibolic pathway rather than only as a catabolic one. |
| Reason (R): | Breaking down processes within the living organism is catabolism, and synthesis is anabolism. |
| 1. | Both (A) and (R) are True and (R) correctly explains (A) |
| 2. | Both (A) and (R) are True but (R) does not correctly explains (A) |
| 3. | (A) is True but (R) is False |
| 4. | (A) is False but (R) is True |
Subtopic: THE RESPIRATORY BALANCE SHEET |
60%
Level 2: 60%+
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In glycolysis:
1. Only I is correct
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect
| I: | ATP is utilised at two steps: first in the conversion of glucose into glucose 6-phosphate and second in the conversion of fructose 6-phosphate to fructose 1, 6-bisphosphate. |
| II: | ATP is produced at two steps: first in the conversion of BPGA to 3-phosphoglyceric acid (PGA), and second during the conversion of PEP to pyruvic acid. |
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect
Subtopic: Glycolysis | Glycolysis Regulation |
91%
Level 1: 80%+
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Enzyme that catalyses the decarboxylation of pyruvic acid to acetaldehyde is:
1. Pyruvate dehydrogenase
2. Pyruvate kinase
3. Pyruvate decarboxylase
4. Pyruvate translocase
1. Pyruvate dehydrogenase
2. Pyruvate kinase
3. Pyruvate decarboxylase
4. Pyruvate translocase
Subtopic: Kreb's Cycle |
62%
Level 2: 60%+
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The reactions catalysed by pyruvic dehydrogenase in aerobic respiration require the participation of several coenzymes, including:
1. Only I
2. Only II and III
3. Only III
4. Only I and II
| I: | FAD |
| II: | NAD+ |
| III: | Coenzyme A. |
1. Only I
2. Only II and III
3. Only III
4. Only I and II
Subtopic: Aerobic Respiration |
84%
Level 1: 80%+
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In a eukaryotic plant cell, within a mitochondrion, the proton gradient develops across the:
1. Inter-membrane space
2. Inner membrane
3. Outer membrane
4. Matrix
1. Inter-membrane space
2. Inner membrane
3. Outer membrane
4. Matrix
Subtopic: ETS:2 | ETS:1 | ETS |
Level 3: 35%-60%
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In the mitochondrial matrix, pyruvate is broken down to release:
1. Only I and II
2. Only III and IV
3. Only I, II and IV
4. Only I and IV
| I: | Three molecules of CO2 |
| II: | Eight molecules of NADH + H+ |
| III: | Two molecules of FADH2 |
| IV: | One molecule of ATP |
1. Only I and II
2. Only III and IV
3. Only I, II and IV
4. Only I and IV
Subtopic: Fermentation | Aerobic Respiration | Oxidative Phosphorylation |
60%
Level 2: 60%+
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Which enzyme/s takes part in both mitochondrial ETS and Kreb’s cycle?
1. Only II
2. Only I and II
3. Only III
4. I, II and III
| I: | NADH dehydrogenase |
| II: | Succinate dehydrogenase |
| III: | Isocitrate dehydrogenase |
2. Only I and II
3. Only III
4. I, II and III
Subtopic: Kreb's Cycle |
51%
Level 3: 35%-60%
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Which component of the mitochondrial ETS is not a protein?
| 1. | Complex I | 2. | Cytochrome c |
| 3. | Ubiquinone | 4. | Complex IV |
Subtopic: ETS:2 | ETS:1 | ETS |
67%
Level 2: 60%+
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