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Q. No.A uniform electric field exists in a certain region of space. The potential at the following points are given (all units are in SI):
• \(A \left ( 1, 0, 0 \right )\) \(V_{A}=2\) volt
• \(B \left ( 0, 2, 0 \right )\) \(V_{B}=4\) volt
• \(C \left ( 0, 0, 2 \right )\) \(V_{C}=6\) volt
• \(D \left ( 1, 1, 0 \right )\) \(V_{D}=-1\) volt
The component of the electric field along the \(x\text-\)axis is:
1. \(2\) V/m
2. \(8\) V/m
3. \(3\) V/m
4. \(-6\) V/m
Subtopic: Relation between Field & Potential |
Level 4: Below 35%
Hints
A parallel plate air capacitor having a plate separation \(d\) is charged, and the energy stored is \(U\). The force between the plates is:
| 1. | \(\dfrac Ud\) | 2. | \(\dfrac {2U}d\) |
| 3. | \(\dfrac U{2d}\) | 4. | \(\dfrac {\sqrt2U}d\) |
Subtopic: Energy stored in Capacitor |
61%
Level 2: 60%+
Hints
Four uncharged capacitors and resistances are connected as shown and a potential difference is applied between \(P\) and \(Q\).
It is observed that \(V_A=V_B\) after a sufficiently long time.
Then:
It is observed that \(V_A=V_B\) after a sufficiently long time.
Then:
| 1. | \(\dfrac{C_1}{C_2}=\dfrac{C_3}{C_4}\) | 2. | \(\dfrac{C_1}{C_2}=\dfrac{R_3~C_3}{R_4~C_4}\) |
| 3. | \(\dfrac{C_1}{C_2}=\dfrac{R_4}{R_3}\) | 4. | \(\dfrac{C_1}{C_2}=\dfrac{R_4~C_3}{R_3~C_4}\) |
Subtopic: Capacitance |
Level 3: 35%-60%
Hints
The arrangement shown in the figure is set up with capacitors initially uncharged, and the circuit is completed. A potential difference is imposed across \(AB\) so that the charge on the upper capacitor is doubled without changing its sign.
Then, \(V_{A}-V_{B}=\)
1. \(E_0\)
2. \(2E_0\)
3. \(-E_0\)
4. zero
Then, \(V_{A}-V_{B}=\)
1. \(E_0\)
2. \(2E_0\)
3. \(-E_0\)
4. zero
Subtopic: Capacitance |
Level 3: 35%-60%
Hints
Three metallic spheres of radii \(r_1,~ r_2,~ r_3\) are connected by very long conducting wires to form an equilateral triangle. The capacitance of the system is:
1. \(4 \pi \varepsilon_{0}\left(r_{1}+r_{2}+r_{3}\right)\)
2. \(4 \pi \varepsilon_{0} \dfrac{r_{1}^{2}+r_{2}^{2}+r_{3}^{2}}{r_{1}+r_{2}+r_{3}}\)
3. \(4 \pi \varepsilon_{0}\left(\dfrac{1}{r_{1}}+\dfrac{1}{r_{2}}+\dfrac{1}{r_{3}}\right)^{-1}\)
4. \(4 \pi \varepsilon_{0} \sqrt{r_{1}^{2}+r_{2}^{2}+r_{3}^{2}}\)
1. \(4 \pi \varepsilon_{0}\left(r_{1}+r_{2}+r_{3}\right)\)
2. \(4 \pi \varepsilon_{0} \dfrac{r_{1}^{2}+r_{2}^{2}+r_{3}^{2}}{r_{1}+r_{2}+r_{3}}\)
3. \(4 \pi \varepsilon_{0}\left(\dfrac{1}{r_{1}}+\dfrac{1}{r_{2}}+\dfrac{1}{r_{3}}\right)^{-1}\)
4. \(4 \pi \varepsilon_{0} \sqrt{r_{1}^{2}+r_{2}^{2}+r_{3}^{2}}\)
Subtopic: Capacitance |
51%
Level 3: 35%-60%
Hints
Four identical point charges (\(q\) each) are placed at the four corners of a square of diagonal \(d.\) The potential at a point which is at a distance \(\dfrac{d}{2}\) above the centre of the square is:
\(\Big(k=\dfrac{1}{4\pi\varepsilon_0}\Big)\)
\(\Big(k=\dfrac{1}{4\pi\varepsilon_0}\Big)\)
| 1. | \(\dfrac{8~kq}{d}\) | 2. | \(\dfrac{4~kq}{d}\) |
| 3. | \(\dfrac{4\sqrt2~kq}{d}\) | 4. | \(\dfrac{\sqrt2~kq}{d}\) |
Subtopic: Electric Potential |
68%
Level 2: 60%+
Hints
The capacitance of the system of three parallel plates of plate area \(A,\) plate separation \(d\) is measured between the center plate \((X)\) and the two outer plates \((Y)\) connected together. It is equal to:
1. \(\dfrac{2\varepsilon_0A}{d}\)
2. \(\dfrac{\varepsilon_0A}{2d}\)
3. \(\dfrac{\varepsilon_0A}{d}\)
4. \(\dfrac{4\varepsilon_0A}{d}\)
1. \(\dfrac{2\varepsilon_0A}{d}\)
2. \(\dfrac{\varepsilon_0A}{2d}\)
3. \(\dfrac{\varepsilon_0A}{d}\)
4. \(\dfrac{4\varepsilon_0A}{d}\)
Subtopic: Capacitance |
68%
Level 2: 60%+
Hints
A non-conducting circular plate is uniformly charged and the potential at its center is \(V_0.\) If all the charge is collected and kept at its edge, then the potential will be:
| 1. | \(2V_0\) | 2. | \(\dfrac{V_0}{2}\) |
| 3. | \(\dfrac{V_0}{3}\) | 4. | \(\dfrac{V_0}{\sqrt2}\) |
Subtopic: Electric Potential |
53%
Level 3: 35%-60%
Hints
The left plate \(A\) of an air capacitor is connected to the positive terminal while the right plate \(B\) is connected to the negative terminal of a cell of voltage \(V_0.\) Assume that the plate area is \(A,\) and the plate separation is \(d.\) If a slab of dielectric constant \(K\) is inserted into the space between the plates, the electric field in the dielectric will be: (compared to the air capacitor)
| 1. | more. |
| 2. | less. |
| 3. | equal. |
| 4. | more or less or equal depending on the value of \(K\). |
Subtopic: Dielectrics in Capacitors |
Level 3: 35%-60%
Hints
The equivalent capacitance of the circuit between the points \(A~\text{and}~B\) is equal to:
1. \(2C\)
2. \(\dfrac{3C}{2}\)
3. \(3C\)
4. \(\dfrac{5C}{2}\)
1. \(2C\)
2. \(\dfrac{3C}{2}\)
3. \(3C\)
4. \(\dfrac{5C}{2}\)
Subtopic: Combination of Capacitors |
65%
Level 2: 60%+
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