The significant figures present in the answer of the following calculations
is-
\(\frac{2.5 \times 1.25 \times 3.5}{2.01}\)
1. 3
2. 1
3. 2
4. 0
Subtopic: Introduction |
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Determine the average atomic mass (in units) of hydrogen using the following data:
1. 1.00015
2. 1.015
3. 1.0015
4. 1.0005
| Isotope | % Natural Abundance | Molar mass |
| 1H | 99.985 | 1 |
| 2H | 0.015 | 2 |
1. 1.00015
2. 1.015
3. 1.0015
4. 1.0005
Subtopic: Introduction |
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Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below:
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
The mass of CaCl2 formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3 will be -
1. 2.06 g
2. 20.6 g
3. 1.54 g
4. 10.54 g
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
The mass of CaCl2 formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3 will be -
1. 2.06 g
2. 20.6 g
3. 1.54 g
4. 10.54 g
Subtopic: Limiting Reagent |
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Which pair of molecules does not support the law of multiple proportions?
1. CO and CO22. H2O2 and H2O
3. SO2 and SO3
4. NO2- ion and NO2
Subtopic: Introduction |
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Subtopic: Concentration Based Problem |
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Subtopic: Concentration Based Problem |
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Level 1: 80%+
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Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
54%
Level 3: 35%-60%
NEET - 2022
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Match List-I with List-II:
| List-I (Quantities) |
List-II (Corresponding Values) |
||
| (a) | 4.48 litres of O2 at STP | (i) | 0.2 mole |
| (b) | 12.022 × 1022 molecules of H2O | (ii) | 12.044 × 1023 molecules |
| (c) | 96 g of O2 | (iii) | 6.4 g |
| (d) | 88 g of CO2 | (iv) | 67.2 litres at STP |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iii) | (iv) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (ii) | (iv) |
Subtopic: Moles, Atoms & Electrons |
Level 3: 35%-60%
NEET - 2022
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Given below are two statements:
| Assertion (A): | Specific gravity is a dimensionless quantity. |
| Reason (R): | Specific gravity is the density of a substance measured with respect to the density of water at 4°C. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True, but (R) is False. |
| 4. | (A) is False, but (R) is True. |
Subtopic: Introduction |
70%
Level 2: 60%+
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Given below are two statements:
In the light of the above statements, choose the correct answer from the options given below:
| Assertion (A): | The molarity of pure water is 55.55 M at 298 K. |
| Reason (R): | Molarity is a temperature-dependent property. |
In the light of the above statements, choose the correct answer from the options given below:
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Concentration Based Problem |
62%
Level 2: 60%+
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