50 ml of HCl (pH=1) is mixed with another 100 ml of HCl (pH=2) then pH of resulting solution will be approximately

(1) 1.2

(2) 1.4

(3) 1.6

(4) 1.8

Concept Videos :-

#8 | Ionic Equlibrium: pH Value
#12 | Ionic Equlibrium: Solved Problems Set 1
#13 | Ionic Equlibrium: Solved Problems Set 2

Concept Questions :-

(2)

For pH=1,     N=10-1

For pH =2,    N=10-2

N1V1 + N2V2 = NV

10-1 X 50 + 10-2 X 100 = N X 150

N=4 X 10-2

pH =-log[H+] = -log4 X 10-2

pH=1.4

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