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The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is:

1. 44% 2. 49 %
3. 47 % 4. 41 %

Subtopic:  Concentration Terms & Henry's Law |
 58%
Level 3: 35%-60%
JEE
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At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be:
(molar mass of urea = 60 g mol–1)

1. 0.031 mmHg 2. 0.017 mmHg
3. 0.028 mmHg 4. 0.027 mmHg
Subtopic:  Relative Lowering of Vapour Pressure |
 80%
Level 1: 80%+
JEE
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The correct option for the value of vapour pressure of a solution at 45 °C with benzene to octane in a molar ratio 3:2 is:

[At 45 °C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
1. 336 mm of Hg
2. 350 mm of Hg
3. 160 mm of Hg
4. 168 mm of Hg

Subtopic:  Raoult's Law |
 76%
Level 2: 60%+
NEET - 2021
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The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The decreasing order of osmotic pressures of these solutions is:

1. P2 > P3 > P1 2. P3 > P1 > P2
3. P2 > P1 > P3 4. P1 > P2 > P3
Subtopic:  Osmosis & Osmotic Pressure |
 73%
Level 2: 60%+
NEET - 2021
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Which graph represents the positive deviation of vapor pressure?

1.  2.
3. 4. None of the above
Subtopic:  Raoult's Law |
 89%
Level 1: 80%+
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The correct match for the below table is:
Type of solution  Example
a. Solid in gas i. Aerated water
b. Gas in liquid  ii. Smoke
c. Liquid in solid iii. Solution of hydrogen in palladium 
d. Gas in solid iv. Amalgams
   
a b c d
1. i iii iv ii
2. ii i iv iii
3. iii i iv ii
4. iv i ii iii
Subtopic:  Introduction & Colligative properties |
 77%
Level 2: 60%+
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To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:

1. Raoult's law 2. Henry's law
3. Ideal gas Equation 4. All of the above
Subtopic:  Concentration Terms & Henry's Law |
 85%
Level 1: 80%+
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The solubility of a gas in a liquid decreases with an increase in temperature because:

1. Dissolution of a gas in a liquid is an endothermic process. 
2. Dissolution of a gas in a liquid is an exothermic process. 
3. Gases are highly compressible.
4. All of the above.
Subtopic:  Introduction & Colligative properties |
 72%
Level 2: 60%+
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Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:

1. 1.85 × 105

2. 192 × 104

3. 178 × 105

4. 18.7 × 10–5

Subtopic:  Concentration Terms & Henry's Law |
 75%
Level 2: 60%+
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The type of inter-molecular interactions present in:

(a) n-Hexane and n-octane (i) Van der Waal’s forces of attraction
(b) NaClO4 and water (ii) Ion-dipole interaction
(iii) Dipole-dipole interaction
 
(a) (b)
1. (i) (ii)
2. (ii) (ii)
3. (i) (iii)
4. (iii) (iii)
Subtopic:  Azeotrope |
 65%
Level 2: 60%+
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