The major component of air is nitrogen with approximately 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K. if the Henry’s law constant for nitrogen at 298 K is 6.51 × 10⁷ mm respectively, then the composition of nitrogen in air will be :

1. 12.4 × 10⁻⁵

2. 9.22 × 10⁻⁵

3. 3.54 × 10⁻⁵

4. 4.96 × 10⁻⁵

The amount of CaCl₂ (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27 °C is:

If 22 g of benzene is dissolved in 122 g of CCl₄, the mass percentage of CCl₄ and benzene respectively are-

1. $15.28$ $\%,$ $84.\mathrm{72<mspace\; width="1em"></mspace>}\%$ $$

2. $84.72$ $\%,$ $15.28$ $\%$

3. $8.72$ $\%,$ $91.\mathrm{28<mspace\; width="1em"></mspace>}\%$

4. 91.28 %, 8.72 %

The type of inter molecular interactions present in

What is the mole fraction of benzene in a solution where benzene constitutes 30% by mass in carbon tetrachloride (\(\text{CCl}_4\))?

1. 0.46

2. 0.64

3. 0.91

4. 0.19

What mass of urea is needed to prepare 2.5 kg of a 0.25 m aqueous solution?

The molarity of a 20% (mass/mass) KI solution with a density of 1.202 g/mL will be:

1. 2.34 M

2. 1.45 M

3. 3.32 M

4. 0.23 M

The solubility of H₂S in water at STP is 0.195 m. The value of Henry's constant is-

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. The mass percentage of the solvent in resulting solution is:

1. 66.43 %

2. 36.54 %

3. 12.45 %

4. 33.97 %

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K. The composition of the liquid mixture if total vapour pressure is 600 mm Hg is:

$1.<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{A}}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>=0.2<mspace\; width="1em"></mspace>;<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{B}<mspace\; width="1em"></mspace>}=<mspace\; width="1em"></mspace>0.8$
$2.<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{A}}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>0.8<mspace\; width="1em"></mspace>;<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{B}}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>0.2$
$3.<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{A}<mspace\; width="1em"></mspace>}=<mspace\; width="1em"></mspace>0.4<mspace\; width="1em"></mspace>;<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{B}}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>0.6$
$4.<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{A}<mspace\; width="1em"></mspace>}=<mspace\; width="1em"></mspace>0.6<mspace\; width="1em"></mspace>;<mspace\; width="1em"></mspace>{\mathrm{x}}_{\mathrm{B}<mspace\; width="1em"></mspace>}=<mspace\; width="1em"></mspace>0.4$
$$