The correct hybridization states of carbon atoms in C₆H₆ is/are:

1.  sp² 

2. sp

3. sp³

4.  All of the above

Structure 1.
Structure 2.

The Correct IUPAC names of the above structures are-

1. 2, 3–dimethyl butanal & Heptan–4–one

2. 2, 4–dimethyl butanal & Heptan–2–one

3. 2, 3–dimethyl butanal & Heptan–3–one

4. 1, 2 –dimethyl butanal & Heptan–4–one

The IUPAC name of the following compound is -

1.  4,4-Dimethyl-3-hydroxybutanoic acid
2. 2-Methyl-3-hydroxypentan-5-oic acid
3. 4-Methyl-3-hydroxypentanoic acid
4. 3-Hydroxy-4-methylpentanoic acid

The compound which shows metamerism is: 

The correct structure of 2,6-Dimethyl-dec-4-ene is:

1.		2.
3.		4.

a. HC≡CCH=CHCH₃ contains 10 σ bonds and 3 π bonds.

b. CH₂=C=CHCH₃ contains 7 σ bonds and 2 π bonds.

Correct among the above mentioned statement is -

1. Only statement 'a' is true.

2. Only statement 'b' is true

3. Both statements are true

4. Both statements are false

The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{ \; \; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$
 

$O$
$\left|\right|$
$\underset{1}{C}{H}_3—\underset{2}{C}—\underset{3}{C}{H}_3$

The correct hybridization  of carbon atoms are-

1. C₁= sp , C₂= sp³ , C₂= sp²

2. C₁= sp² , C₂= sp³ , C₂= sp³

3. C₁= sp³ , C₂= sp² , C₂= sp³

4. C₁= sp³ , C₂= sp³ , C₂= sp³

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -$\stackrel{1}{\mathrm{ \; C}}{H}_3-\stackrel{}{C}$ $2H=\stackrel{3}{C}{H}_2$

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are -