The correct hybridization of carbon atoms are-
1. C1= sp , C2= sp3 , C2= sp2
2. C1= sp2 , C2= sp3 , C2= sp3
3. C1= sp3 , C2= sp2 , C2= sp3
4. C1= sp3 , C2= sp3 , C2= sp3
The correct hybridization states of carbon atoms in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C 3 = sp3 |
3. | C1= sp2 , C2= sp2 , C 3 = sp | 4. | C1= sp3 , C2= sp3 , C 3 = sp3 |
The correct hybridization states of carbon atoms in C6H6 is/are:
1. sp2
2. sp
3. sp3
4. All of the above
Structure 1. | |
Structure 2. |
The Correct IUPAC names of the above structures are-
1. 2, 3–dimethyl butanal & Heptan–4–one
2. 2, 4–dimethyl butanal & Heptan–2–one
3. 2, 3–dimethyl butanal & Heptan–3–one
4. 1, 2 –dimethyl butanal & Heptan–4–one
The IUPAC name of the following compound is -
1. 4,4-Dimethyl-3-hydroxybutanoic acid
2. 2-Methyl-3-hydroxypentan-5-oic acid
3. 4-Methyl-3-hydroxypentanoic acid
4. 3-Hydroxy-4-methylpentanoic acid
The compound which shows metamerism is:
1. | C3H6O | 2. | C4H10O |
3. | C5H12 | 4. | C3H8O |
The correct structure of 2,6-Dimethyl-dec-4-ene is:
1. | 2. | ||
3. | 4. |
a. HC≡CCH=CHCH3 contains 10 σ bonds and 3 π bonds.
b. CH2=C=CHCH3 contains 7 σ bonds and 2 π bonds.
Correct among the above mentioned statement is -
1. Only statement 'a' is true.
2. Only statement 'b' is true
3. Both statements are true
4. Both statements are false
The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C3= sp3 |
3. | C1= sp3 , C2= sp2 , C3= sp2 | 4. | C1= sp3 , C2= sp3 , C3= sp3 |
The correct hybridization states of carbon atoms in the above compound are -
1. | C1= sp , C2= sp3 | 2. | C1= sp2 , C2= sp |
3. | C1= sp3 , C2= sp | 4. | C1= sp , C2= sp2 |