The coordination compound that will give four isomers is:

1. [Fe(en)₃]Cl₃

2. [Co(en)₂Cl₂]Cl

3. [Fe(PPh₃)₃NH₃ClBr]Cl

4. [Co(PPh₃)₃Cl]Cl₃

The IUPAC name of $\left[Co{\left(N{H}_3\right)}_{3}ClBrN{O}_2\right]$ will be:

1. Triamminebromochloronitrocobaltate (III)
2. Triamminebromochloronitrocobalt (III)
3. Triamminebromonitrochlorocobalt (III)
4. Triamminenitrobromochlorocobalt (III)

$[Cu{\left(N{H}_3\right)}_4{]}^{+2}$ reacts with $HN{O}_3$ in excess of water and gives: 

1. $Cu{\left(OH\right)}_2$

2. $Cu{\left(N{O}_3\right)}_2$

3. $Cu{\left(H_{2}O\right)}^{-2}$

4. None of the above 

In [Cr(NH₃)₆](Br)₃, number of unpaired electrons in Cr is:

Anticancer agent among the following is:

1.		2.
3.		4.

The strong field nature of CN⁻ as a ligand can be attributed to:

1. It is a pseudohalide.

2. It can accept electrons from metal species.

3. It forms high-spin complexes with metal species.

4. It possesses a negative charge.

Considering H₂O as a weak field ligand, the number of unpaired electrons in \([Mn(H_{2}O)_{6}]^{2+}\) will be:
(At. no. of Mn = 25)

Among [Ni(CO)₄], [Ni(CN)₄]²⁻, [ NiCl₄]²⁻ species, the hybridization states of the Ni atom are respectively:
(At. No. of Ni = 28)

Coordination compound that would exhibit optical isomerism is:

The atomic numbers of Cr and Fe are respectively 24 and 26. Among the following, the one that is paramagnetic with the spin of the electron is:

1. CrCO₆

2. FeCO₅

3. [Fe(CN)₆]^4-

4. [Cr(NH₃)₆]³⁺