The electric potential at the surface of a charged solid sphere of insulator is 20V. The value of electric potential at its centre will be

1.  30V

2.  20V

3.  40V

4.  Zero

Subtopic:  Electric Potential |
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The capacitance of a parallel plate capacitor is C. If a dielectric slab of thickness equal to one-fourth of the plate separation and dielectric constant K is inserted between the plates, then new capacitance become

1. KC2K+1

2. 2KCK+1

3. 5KC4K+1

4. 4KC3K+1

Subtopic:  Dielectrics in Capacitors |
 68%
From NCERT
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The electric potential at a point at distance 'r' from a short dipole is proportional to

(1) r2

(2) r-1

(3) r-2

(4) r1

Subtopic:  Electric Potential |
 63%
From NCERT
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A hollow charged metal spherical shell has radius R. If the potential difference between its surface and a point at a distance 3R from the center is V, then the value of electric field intensity at a point at distance 4R from the center is

1.  3V19R

2.  V6R

3.  3V32R

4.  3V16R

Subtopic:  Electric Potential |
 52%
From NCERT
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Capacitors C1=10μF and C2=30μF are connected in series across a source of emf 20KV. The potential difference across C1 will be

(1) 5 KV

(2) 15 KV

(3) 10 KV

(4) 20 KV

Subtopic:  Combination of Capacitors |
 77%
From NCERT
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The equivalent capacitance between A and B is as the given figure:

(1) 16π0r

(2) 4π0r

(3) 8π0r

(4) None of these

Subtopic:  Combination of Capacitors |
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Two metallic spheres of radii 2cm and 3cm are given charges 6mC and 4mC respectively. The final charge on the smaller sphere will be if they are connected by a conducting wire

(1) 4mC

(2) 6mC

(3) 5mC

(4) 10mC

Subtopic:  Electric Potential |
 57%
From NCERT
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When a proton at rest is accelerated by a potential difference \(V\), its speed is found to be \(v\). The speed of an \(\alpha-\textit{particle}\) when accelerated by the same potential difference from rest will be: 

1. \(V\) 2. \(v \over \sqrt{2}\)
3. \(v \sqrt{2}\) 4. \(2V\)
Subtopic:  Electric Potential |
 60%
From NCERT
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In the circuit shown in figure, energy stored in 6 μF capacitor will be:
 

1. \(48 \times10^{-6}~ \mathrm J\) 2. \(32 \times10^{-6}~ \mathrm J\)
3. \(96 \times10^{-6}~ \mathrm J\) 4. \(24 \times10^{-6}~ \mathrm J\)
Subtopic:  Energy stored in Capacitor |
 64%
From NCERT
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The figure shows some of the equipotential surfaces. Magnitude and direction of the electric field is given by

              

1.  200 V/m, making an angle 1200 with the x-axis

2. 100 V/m, pointing towards the negative x-axis

3. 200 V/m, making an angle -600 with the x-axis

4. 100 V/m, making an angle 300 with the x-axis

Subtopic:  Relation between Field & Potential |
 58%
From NCERT
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