Two solid conductors are made up of the same material and have the same length and the same resistance. One of them has a circular cross-section of area \(  𝐴 _1\) and the other one has a square cross-section of area \(A_2.\) The ratio of \(𝐴 _1 / 𝐴 _2  \) is:

1.	\(1.5\)	2.	\(1\)
3.	\(0.8\)	4.	\(2\)

For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:

The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:

For the circuit shown in the figure, the current \(I\) will be:

The colour code of resistance is given below:

The values of resistance and tolerance, respectively are:

1.  47 k$\mathrm{\Omega }$, 10%

2.  4.7 k$\mathrm{\Omega }$, 5%

3.  470 $\mathrm{\Omega }$, 5%

4.  470 k$\mathrm{\Omega }$, 5%

A resistance wire connected in the left gap of a meter bridge balances a \(10~\Omega\) $$resistance in the right gap at a point which divides the bridge wire in the ratio \(3:2\). lf the length of the resistance wire is \(1.5~\text{m}\), then the length of \(1~\Omega\) of the resistance wire will be:
1. \(1.0\times 10^{-1}~\text{m}\) 
2. \(1.5\times 10^{-1}~\text{m}\)
3. \(1.5\times 10^{-2}~\text{m}\)
4. \(1.0\times 10^{-2}~\text{m}\)

A charged particle having drift velocity of \(7.5\times10^{-4}~\text{ms}^{-1}\) in an electric field of \(3\times10^{-10}~\text{Vm}^{-1},\) has mobility of: 
1. \(2.5\times 10^{6}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)
2. \(2.5\times 10^{-6}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)
3. \(2.25\times 10^{-15}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)
4. \(2.25\times 10^{15}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)

Which of the following graph represents the variation of resistivity ($\rho$) with temperature (\(T\)) for copper?

1.		2.
3.		4.

The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?

The reading of an ideal voltmeter in the circuit shown is: