The disproportionation reaction of is as follows:
X and Y in the above reaction are:
1. H3PO2, HPO2
2. H3PO4, PH3
3. H2PO6, PO3
4. None of the above.
The condition that does not exist in the Haber process
for the manufacturing of ammonia is:
1. Pressure (around 200 ×105 Pa)
2. Temperature (700 K)
3. Catalyst such as iron oxide.
4. Presence of inert gases.
The reason behind carbon showing catenation property but lead does not is:
1. Due to the smaller size of C than that of Pb
2. Due to the smaller size of Pb than that of C
3. Due to the smaller ionization energy of C than that of Pb
4. Due to the inert pair effect
Assertion (A): | Both rhombic and monoclinic sulphur exist as S8 but oxygen exists as O2. |
Reason (R): | Oxygen forms pπ - pπ multiple bonds due to its small size and small bond length but pπ - pπ bonding is not possible in sulphur. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
Identify the correct statements among the following:
a. | CO2 (g) is used as a refrigerant for ice-cream and frozen food. |
b. | The structure of C60 contains twelve six-carbon rings and twenty five-carbon rings. |
c. | ZSM-5, a type of zeolite, is used to convert alcohol into gasoline. |
d. | CO is a colourless and odourless gas |
1. (a) and (c) only
2. (b) and (c) only
3. (c) and (d) only
4. (a), (b) and (c) only
Match the compounds of Xe in Column I with the molecular structure in Column II.
Column-I | Column-II | ||
(a) | XeF2 | (i) | Square planar |
(b) | XeF4 | (ii) | Linear |
(c) | XeO3 | (iii) | Square pyramidal |
(d) | XeOF4 | (iv) | Pyramidal |
(a) | (b) | (c) | (d) | |
1. | (ii) | (i) | (iii) | (iv) |
2. | (ii) | (iv) | (iii) | (i) |
3. | (ii) | (iii) | (i) | (iv) |
4. | (ii) | (i) | (iv) | (iii) |
A solid (A) reacts with strong aqueous NaOH, liberating a foul smelling gas (B), which spontaneously burns in the air, giving smoky rings. A and B are, respectively:
1. P4 (red) and PH3
2. P4 (white) and PH3
3. S8 and H2S
4. P4 (white) and H2S
The basic structural unit of silicates is-
1. | \( \mathrm{SiO}_4{}^{4-}\) | 2. | \(\left(\mathrm{SiO}_3\right)^{2-} \) |
3. | \(\mathrm{SiO}_4{ }^{2-} \) | 4. | \(\mathrm{SiO}^{-}\) |
is -
1. A Monobasic acid and a weak Lewis acid.
2. A Monobasic and a weak Bronsted acid..
3. A Monobasic and a strong Lewis acid.
4. A Tribasic and a weak Bronsted acid.
Incorrect order among the following is:
1. | F2 > Cl2 > Br2 > I2 | Oxidising power |
2. | F < Cl > Br > I | Electron gain enthalpy |
3. | F2 > Cl2 > Br2 > I2 | Bond dissociation energy |
4. | F> Cl > Br > I | Electronegativity |