(a) | \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\) |
(b) | \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\) |
(c) | \(E_{Cr^{3+}/Cr}^o = -0.74\ V\) |
Based on standard electrode potentials given above, the correct arrangement for increasing order of reducing power of
elements is:
1. | \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \) |
2. | \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\) |
3. | \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \) |
4. | \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\) |
The oxidation state of two S-atoms in is:
1. +2 and +4
2. +3 and -2
3. +4 and -2
4. +6 and -2
the oxidation state of P in ?
1. +2
2. +3
3. +4
4. +5
The oxidation state of P in is-
1. | +3 | 2. | +4 |
3. | +2 | 4. | +5 |
Nitric acid reacts with PbO but does not react with PbO2 , because -
1. PbO is a base while PbO2 is a strong oxidizing reagent
2. PbO is a base while PbO2 is a weak oxidizing reagent
3. PbO is neutral while PbO2 is a strong oxidizing reagent
4. PbO is acid while PbO2 is a strong oxidizing reagent
1. | Due to manganese being in its highest oxidation state in MnO₄²⁻. |
2. | Due to manganese being in its highest oxidation state in MnO₄⁻ |
3. | Because the disproportionation reaction of MnO₄²⁻ is endothermic. |
4. | Because the disproportionation reaction of MnO₄²⁻ is exothermic. |
In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?
Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)
1. ClO-
2. Cl2
3. Cl-
4. Both ClO- and Cl-
The compound AgF2 (unstable) acts as a/ an:
1. Oxidising agent.
2. Reducing agent.
3. Both oxidising and reducing agent.
4. Neither oxidising and reducing agent.
Among the following hydrohalic compounds, the best reductant is -
KMnO4 (mol. wt=158) oxidizes oxalic acid in acidic medium to CO2 and water as follows.
What is the equivalent weight of KMnO4?
1. 158
2. 31.6
3. 39.5
4. 79