Doping affects the property of semiconductors. It -

1. Increases the conductivity of semiconductors.

2. Decreases the conductivity of semiconductors.

3. No effect on conductivity of semiconductors.

4. None of the above.

Subtopic:  Magnetic Behaviour of an Element/Compound |
 90%
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Non-stoichiometric defect present in the sample of ferrous oxide with formula Fe0.93O1.00  - 

1. Metal deficiency defect

2. Metal excess defect 

3. Frenkel defect

4. Schottky defect

Subtopic:  Imperfections in Solids & Semiconductors |
 83%
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Select the correct option based on statements below:

Assertion (A): The stability of a crystal is reflected by the magnitude of its melting point.
Reason (R): Greater the intermolecular forces of attraction, the higher will be the stability and melting point of the substance.
 
1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. Both (A) and (R) are false.
Subtopic:  Introduction & Crystal System |
 87%
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The packing efficiency of the face-centered cubic unit cell is:
(assuming that the atoms are touching each other)

1. 52.40 %

2. 68.04 %

3. 74 %

4. 79.06 %

Subtopic:  Density & Packing Fraction |
 85%
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Silver crystallizes in fcc lattice. If the edge length of the cell is 4.07 × 10−8 cm and density is 10.5 g cm−3, the atomic mass of silver is -

1. 120.31 g mol-1

2. 107.9 g mol-1

3. 207.60 g mol-1

4. 138.52 g mol-1

Subtopic:  Density & Packing Fraction |
 81%
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Copper crystallizes into an fcc lattice with an edge length of 3.61 × 10−8 cm. The density of copper crystal will be - 

1. 7.46 g cm-3

2. 9.67 g cm-3

3. 8.96 g cm-3

4. 5.63 g cm-3

Subtopic:  Density & Packing Fraction |
 50%
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Nickel oxide has the formula Ni0.98O1.00. The fraction of nickel existing as Ni3+ ions will be -

1. 0.041

2.  0.959

3. 0.736 

4. 0.264 

 

Subtopic:  Imperfections in Solids & Semiconductors |
 65%
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A ferric oxide crystallizes in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. The formula of the ferric oxide is-

1. FeO

2. Fe2O3

3. Fe3O4

4. Fe3O2

Subtopic:  Voids, Radius Ratio & Coordination Number |
 72%
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A compound forms a hexagonal close-packed structure. The total number of voids in 0.5 moles

of the compound will be -

1. 9.033 × 1023
2. 3.011 × 1023
3. 6.023 × 1023
4. 8.024 × 1023

Subtopic:  Voids, Radius Ratio & Coordination Number |
 53%
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A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. The formula of the compound would be -

1. MN

2. M3N4

3. M2N3

4. M3N2

Subtopic:  Voids, Radius Ratio & Coordination Number |
 76%
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