The oxidation state of P in HPO32- is-

1. +3 2. +4
3. +2 4. +5

Subtopic:  Introduction to Redox and Oxidation Number |
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Level 1: 80%+
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the oxidation state of P in PO43-?

1. +2

2. +3

3. +4

4. +5

Subtopic:  Oxidizing & Reducing Agents |
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The oxidation state of two S-atoms in Na2S2O3 is:

1. +2 and +4

2. +3 and -2

3. +4 and -2

4. +6 and -2

Subtopic:  Introduction to Redox and Oxidation Number |
Level 3: 35%-60%
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Consider the standard electrode potentials given below:
(a) \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\)
(b) \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\)  
(c) \(E_{Cr^{3+}/Cr}^o = -0.74\ V\)


The correct arrangement of increasing order for reducing power of elements is:

1. \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \)
2. \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\)
3. \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \)
4. \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\)
Subtopic:  Emf & Electrode Potential |
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Nitric acid reacts with PbO but does not react with PbO, because -

1. PbO is a base while PbO2 is a strong oxidizing reagent

2. PbO is a base while PbO2 is a weak oxidizing reagent

3. PbO is neutral while PbO2 is a strong oxidizing reagent

4. PbO is acid while PbO2 is a strong oxidizing reagent

Subtopic:  Oxidizing & Reducing Agents |
 62%
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Why does the MnO₄²⁻ ion undergo disproportionation in an acidic medium, whereas the MnO₄⁻ ion does not?
1.  Due to manganese being in its highest oxidation state in MnO₄²⁻.
2.  Due to manganese being in its highest oxidation state in MnO₄⁻
3.  Because the disproportionation reaction of MnO₄²⁻ is endothermic.
4.  Because the disproportionation reaction of MnO₄²⁻ is exothermic.
Subtopic:  Introduction to Redox and Oxidation Number |
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In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?
Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)

1. ClO- 

2. Cl2

3. Cl-

4. Both ClO- and Cl-

Subtopic:  Oxidizing & Reducing Agents |
 50%
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KMnO4 (mol. wt=158) oxidizes oxalic acid in acidic medium to CO2 and water as follows.

5C2O42-+2MnO4-+16H+10CO2+2Mn2++8H2O

What is the equivalent weight of KMnO4?

1. 158

2. 31.6

3. 39.5

4. 79

Subtopic:  Equivalent Weight |
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An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is

1. 4 mL

2. 20 mL

3. 40 mL

4. 60 mL

Subtopic:  Equivalent Weight |
 58%
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The equivalent weight of MnSO4 is half its molecular weight when it is converted to

1. MnO

2. MnO42-

3. MnO2

4. MnO4-

Subtopic:  Equivalent Weight |
 71%
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