Nitric acid reacts with PbO but does not react with PbO2 , because -
1. PbO is a base while PbO2 is a strong oxidizing reagent
2. PbO is a base while PbO2 is a weak oxidizing reagent
3. PbO is neutral while PbO2 is a strong oxidizing reagent
4. PbO is acid while PbO2 is a strong oxidizing reagent
The oxidation state of P in is-
1. | +3 | 2. | +4 |
3. | +2 | 4. | +5 |
the oxidation state of P in ?
1. +2
2. +3
3. +4
4. +5
The oxidation state of two S-atoms in is:
1. +2 and +4
2. +3 and -2
3. +4 and -2
4. +6 and -2
(a) | \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\) |
(b) | \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\) |
(c) | \(E_{Cr^{3+}/Cr}^o = -0.74\ V\) |
Based on standard electrode potentials given above, the correct arrangement for increasing order of reducing power of
elements is:
1. | \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \) |
2. | \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\) |
3. | \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \) |
4. | \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\) |
1. | Due to manganese being in its highest oxidation state in MnO₄²⁻. |
2. | Due to manganese being in its highest oxidation state in MnO₄⁻ |
3. | Because the disproportionation reaction of MnO₄²⁻ is endothermic. |
4. | Because the disproportionation reaction of MnO₄²⁻ is exothermic. |
In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?
Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)
1. ClO-
2. Cl2
3. Cl-
4. Both ClO- and Cl-
KMnO4 (mol. wt=158) oxidizes oxalic acid in acidic medium to CO2 and water as follows.
What is the equivalent weight of KMnO4?
1. 158
2. 31.6
3. 39.5
4. 79
An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is
1. 4 mL
2. 20 mL
3. 40 mL
4. 60 mL
The equivalent weight of MnSO4 is half its molecular weight when it is converted to
1. MnO
2.
3.
4.