The three stable isotopes of neon: ${}_{10}{}^{20}Ne, {}_{10}{}^{21}Ne, and {}_{10}{}^{22}Ne$ have respective abundances of 90.51%, 0.27%, and 9.22%. The atomic masses of the three isotopes are 19.99 u, 20.99 u, and 21.99 u, respectively. The average atomic mass of neon is:

1. 20.1709 u
2. 21.7037 u
3. 20.1771 u
4. 21.0097 u

What is the binding energy (in MeV) of a nitrogen nucleus ${}_7{}^{14}N$?

$\mathrm{Given},$
${\mathrm{m}}_{\mathrm{p}} = 1.007825 \mathrm{u}$
${\mathrm{m}}_{\mathrm{n}} = 1.008665 \mathrm{u}$
$\mathrm{m}\left({}_7{}^{14}\mathrm{N}\right) = 14.003074 u$

1. 102.7 MeV.
2. 100.7 MeV.
3. 104.7 MeV.
4. 108.7 MeV.

A radioactive isotope has a half-life of T years. How long will it take the activity to reduce to 3.125% of its original value?

1. T years.
2. 4T years.
3. 3T years.
4. 5T years.

What is the amount of ${}_{27}{}^{60}Co$ necessary to provide a radioactive source of 8.0 mCi strength? The half-life of ${}_{27}{}^{60}Co$ is 5.3 years.

1. $8.109\times {10}^{-6} g$
2. $7.106\times {10}^{-6} g$ 
3. $7.105\times {10}^{-5} g$
4. $8.107\times {10}^{-5} g$

A given coin has a mass of 3.0 g. How much nuclear energy would be required to separate all the neutrons and protons from each other? For simplicity assume that the coin is entirely made of ${}_{29}{}^{63}Cu$ atoms (of mass 62.92960 u).

$\mathrm{Mass} \mathrm{of} \mathrm{proton}, {\mathrm{m}}_{\mathrm{p}} = 1.00783 \mathrm{u}$
$\mathrm{Mass} \mathrm{of} neutr\mathrm{on}, {\mathrm{m}}_{\mathrm{n}} = 1.00867 \mathrm{u}$

1. \(2.5296\times10^{12}\) MeV
2. \(1.581\times10^{25}\)  MeV
3. \(3.1223\times10^{20}\) MeV
4. \(931.02\times10^{19}\) MeV

The amount of ${}_{27}{}^{60}Co$ necessary to provide a radioactive source of 8.0 mCi strength is:

(The half-life of ${}_{27}{}^{60}Co$ is 5.3 years)

1.  \(6.3\times10^{-6}\) g
2. \(7.1\times10^{-6}\) g
3. \(5.7\times10^{-6}\) g
4. \(6.9\times10^{-6}\) g

The half-life of ${}_{38}{}^{90}Sr$ is 28 years. What is the disintegration rate of 15 mg of this isotope?
1. \(9.64 \times 10^{10}~\mathrm{atoms} / \mathrm{s}\)
2. \(11.12 \times 10^{11}~\mathrm{atoms} / \mathrm{s}\)
3. \(7.87 \times 10^{10}~\mathrm{atoms}/ \mathrm{s}\)
4. \(10.04 \times 10^{11}~\mathrm{atoms}/ \mathrm{s}\)

The approximately nuclear radii ratio of the gold isotope ${}_{79}{}^{197}Au$ and the silver isotope ${}_{47}{}^{107}Ag$ is:

1. 1:1.23
2. 1:1.32
3. 1.01:1
4. 1.22:1

The radionuclide \(^{11}_{6}C\) decays according to \(^{11}_{6}C \rightarrow ~^{11}_{5}B+e^{+}+\nu\): \(\left(T_{\frac{1}{2}}=20.3~\text{min}\right)\)
The maximum energy of the emitted position is \(0.960~\text{MeV}\).
Given the mass values: \(m\left(_{6}^{11}C\right) = 11.011434~\text{u}~\text{and}~ m\left(_{6}^{11}B\right) = 11.009305~\text{u},\)
The value of \(Q\) is:
1. \(0.313~\text{MeV}\)
2. \(0.962~\text{MeV}\)
3. \(0.414~\text{MeV}\)
4. \(0.132~\text{MeV}\)

The nucleus ${}_{10}{}^{23}\mathrm{Ne}$ decays by β– emission. What is the maximum kinetic energy of the electrons emitted? Given that:

m (${}_{10}{}^{23}Ne$) = 22.994466 u

m (${}_{11}{}^{23}Na$) = 22.989770 u.

1. 4.201 MeV
2. 3.791 MeV
3. 4.374 MeV
4. 3.851 MeV