What is the amount of ${}_{27}{}^{60}Co$ necessary to provide a radioactive source of 8.0 mCi strength? The half-life of ${}_{27}{}^{60}Co$ is 5.3 years.

1. $8.109\times {10}^{-6} g$
2. $7.106\times {10}^{-6} g$ 
3. $7.105\times {10}^{-5} g$
4. $8.107\times {10}^{-5} g$

A given coin has a mass of 3.0 g. How much nuclear energy would be required to separate all the neutrons and protons from each other? For simplicity assume that the coin is entirely made of ${}_{29}{}^{63}Cu$ atoms (of mass 62.92960 u).

$\mathrm{Mass} \mathrm{of} \mathrm{proton}, {\mathrm{m}}_{\mathrm{p}} = 1.00783 \mathrm{u}$
$\mathrm{Mass} \mathrm{of} neutr\mathrm{on}, {\mathrm{m}}_{\mathrm{n}} = 1.00867 \mathrm{u}$

1. \(2.5296\times10^{12}\) MeV
2. \(1.581\times10^{25}\)  MeV
3. \(3.1223\times10^{20}\) MeV
4. \(931.02\times10^{19}\) MeV

The amount of ${}_{27}{}^{60}Co$ necessary to provide a radioactive source of 8.0 mCi strength is:

(The half-life of ${}_{27}{}^{60}Co$ is 5.3 years)

1.  \(6.3\times10^{-6}\) g
2. \(7.1\times10^{-6}\) g
3. \(5.7\times10^{-6}\) g
4. \(6.9\times10^{-6}\) g

The half-life of ${}_{38}{}^{90}Sr$ is 28 years. What is the disintegration rate of 15 mg of this isotope?
1. \(9.64 \times 10^{10}~\mathrm{atoms} / \mathrm{s}\)
2. \(11.12 \times 10^{11}~\mathrm{atoms} / \mathrm{s}\)
3. \(7.87 \times 10^{10}~\mathrm{atoms}/ \mathrm{s}\)
4. \(10.04 \times 10^{11}~\mathrm{atoms}/ \mathrm{s}\)

The approximately nuclear radii ratio of the gold isotope ${}_{79}{}^{197}Au$ and the silver isotope ${}_{47}{}^{107}Ag$ is:

1. 1:1.23
2. 1:1.32
3. 1.01:1
4. 1.22:1

The radionuclide \(^{11}_{6}C\) decays according to \(^{11}_{6}C \rightarrow ~^{11}_{5}B+e^{+}+\nu\): \(\left(T_{\frac{1}{2}}=20.3~\text{min}\right)\)
The maximum energy of the emitted position is \(0.960~\text{MeV}\).
Given the mass values: \(m\left(_{6}^{11}C\right) = 11.011434~\text{u}~\text{and}~ m\left(_{6}^{11}B\right) = 11.009305~\text{u},\)
The value of \(Q\) is:
1. \(0.313~\text{MeV}\)
2. \(0.962~\text{MeV}\)
3. \(0.414~\text{MeV}\)
4. \(0.132~\text{MeV}\)

The nucleus ${}_{10}{}^{23}\mathrm{Ne}$ decays by β– emission. What is the maximum kinetic energy of the electrons emitted? Given that:

m (${}_{10}{}^{23}Ne$) = 22.994466 u

m (${}_{11}{}^{23}Na$) = 22.989770 u.

1. 4.201 MeV
2. 3.791 MeV
3. 4.374 MeV
4. 3.851 MeV

The fission properties of ${}_{94}{}^{239}Pu$ are very similar to those of ${}_{92}{}^{235}U$. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure ${}_{94}{}^{239}Pu$ undergo fission?

1. \(2.5\times 10^{25}\) MeV
2. \(4.5\times 10^{25}\) MeV
3. \(2.5\times 10^{26}\) MeV
4. \(4.5\times 10^{26}\) MeV

A 1000 MW fission reactor consumes half of its fuel in 5.00 yr. How much ${}_{92}{}^{235}U$ did it contain initially? Assume that the reactor operates 80% of the time, that all the energy generated arises from the fission of, ${}_{92}{}^{235}U$ and that this nuclide is consumed only by the fission process.

1. 4386 kg.
2. 3076 kg.
3. 4772 kg.
4. 8799 kg.

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as:

${}_1{}^{2}H+{}_1{}^{2}H$ $\to$ ${}_2{}^{3}He+n+3.27$ $MeV$.