$\underset{2. {\mathrm{NaHSO}}_3}{\overset{1. {\mathrm{OsO}}_4}{\to }}$ Product of the reaction is :

1.    

2. 

3.      

4. 

 Product; Product is:

MCPBA $\to$Metachloroperbenzoic acid

1. 

2. 

3. 

4. 

What is the major product expected from the following reaction?

$\stackrel{\mathrm{D}-\mathrm{Cl}}{\to }$ Product

1. 

   2. 

3.    

4. 

${\mathrm{CH}}_3-\underset{|}{\mathrm{C}}\mathrm{H}-{\mathrm{CO}}_2\mathrm{K}$
${\mathrm{CH}}_3-\mathrm{CH}-{\mathrm{CO}}_2\mathrm{K}$ $\stackrel{\mathrm{electrolysis}}{\to }$ (A) (Major)

Major product (A) of the above reaction:

$\left(\mathrm{A}\right)\stackrel{Na/N{H}_3\left(l\right)}{\to }\left(B\right)\stackrel{MCBPA}{\to }\left(C\right)$

Compound (C) in above sequence of reaction is:

1.    2. 

3.   4. 

; This conversion can be achieved by:

                                       Lindlar
Br-(CH₂)₁₂-C CH →(A)→(B);Product (B) is :
                           NaNH2   Catalyst
1.2.
3.4. 

(a)(b)(c)(d)

, Product (A) in this reaction is:

1. 

2. 

3. 

4. 

In the above compound Cl will liberated easily in the form of:

1. ${\mathrm{Cl}}^{\oplus }$

2. Cl^-

3. Cl⁰

4. Cl²⁺