The angular speed of a fly wheel making \(120\) revolutions/minute is:
1. \(2\pi~\mathrm{rad/s}\)
2. \(4\pi^2~\mathrm{rad/s}\)
3. \(\pi~\mathrm{rad/s}\)
4. \(4\pi~\mathrm{rad/s}\)

Subtopic:  Circular Motion |
 82%
Level 1: 80%+
PMT - 1995
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Certain neutron stars are believed to be rotating at about \(1\) rev/s. If such a star has a radius of \(20\) km, the acceleration of an object on the equator of the star will be:

1. \(20 \times 10^8 ~\text{m/s}^2\) 2. \(8 \times 10^5 ~\text{m/s}^2\)
3. \(120 \times 10^5 ~\text{m/s}^2\) 4. \(4 \times 10^8 ~\text{m/s}^2\)
Subtopic:  Circular Motion |
 71%
Level 2: 60%+
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An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m, the acceleration of a point on the tip of the blade is about

(1) 1600 m/sec2

(2) 4740 m/sec2

(3) 2370 m/sec2

(4) 5055 m/sec2

Subtopic:  Circular Motion |
 79%
Level 2: 60%+
PMT - 1990
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If ar and at represent radial and tangential accelerations, the motion of a particle will be uniformly circular if 

1. ar = 0 and at = 0

2. ar = 0 but at0

3. ar0 but at = 0

4. ar0 and at0

Subtopic:  Circular Motion |
 71%
Level 2: 60%+
PMT - 2004
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In \(1.0~\text{s}\), a particle goes from point \(A\) to point \(B\), moving in a semicircle of radius \(1.0~\text{m}\) (see figure). The magnitude of the average velocity is:

1. \(3.14~\text{m/s}\) 2. \(2.0~\text{m/s}\)
3. \(1.0~\text{m/s}\) 4. zero
Subtopic:  Speed & Velocity |
 80%
Level 1: 80%+
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The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^3\) and \(y=\beta t^3.\) The speed of the particle at time \(t\) is given by:
1. \(\sqrt{\alpha^2+\beta^2}~\)
2. \(3t\sqrt{\alpha^2+\beta^2}~\)
3. \(3t^2\sqrt{\alpha^2+\beta^2}~\)
4. \(t^2\sqrt{\alpha^2+\beta^2}~\)

Subtopic:  Speed & Velocity |
 81%
Level 1: 80%+
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Figure shows a body of mass m moving with a uniform speed v along a circle of radius r. The change in velocity in going from A to B is 

(1) v2

(2) v/2

(3) v

(4) zero

Subtopic:  Circular Motion |
 65%
Level 2: 60%+
PMT - 2004
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The angle turned by a body undergoing circular motion depends on the time as given by the equation, \(\theta = \theta_{0} + \theta_{1} t + \theta_{2} t^{2}\). It can be deduced that the angular acceleration of the body is? 
1. \(\theta_1\)
2. \(\theta_2\)
3. \(2\theta_1\)
4. \(2\theta_2\)

Subtopic:  Circular Motion |
 85%
Level 1: 80%+
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An aeroplane is flying at a constant horizontal velocity of 600 km/hr at an elevation of 6 km towards a point directly above the target on the earth's surface. At an appropriate time, the pilot releases a ball so that it strikes the target at the earth. The ball will appear to be falling

(1) On a parabolic path as seen by pilot in the plane

(2) Vertically along a straight path as seen by an observer on the ground near the target

(3) On a parabolic path as seen by an observer on the ground near the target

(4) On a zig-zag path as seen by pilot in the plane

Subtopic:  Projectile Motion |
 80%
Level 1: 80%+
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A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is 

(1) 25o8'

(2) 33o7'

(3) 42o8'

(4) 53o8'

Subtopic:  Projectile Motion |
 69%
Level 2: 60%+
AIIMS - 1998
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