The standard electrode potential (E°) values of  Al³⁺/ Al,  Ag⁺ / Ag, K⁺ / K,  and Cr³⁺ / Cr are –1.66 V, 0.80 V, –2.93 V, & –0.79 V respectively. The correct decreasing order of the reducing power of the metals is:

1.	Ag > Cr > Al > K	2.	K > Al > Cr > Ag
3.	K > Al > Ag > Cr	4.	Al > K > Ag > Cr

The oxidation state of Cr in ${\mathrm{CrO}}_6$ is:

The species that does not contain peroxide ions is:

(1) PbO₂

(2) H₂O₂

(3) SrO₂

(4) BaO₂

Equivalent weight of ${\mathrm{FeS}}_2$ in the half reaction, ${\mathrm{FeS}}_2\to {\mathrm{Fe}}_2{\mathrm{O}}_3+{\mathrm{SO}}_2$ is :

1. M/10

2. M/11

3. M/6

4. M/1

When potassium permangante is titrated against ferrous ammonium sulphate in acidic medium, the equivalent weight of potassium permanganate is :

1. $\frac{\mathrm{molecular}<mspace\; width="1em"></mspace>\mathrm{weight}}{3}$

2. $\frac{\mathrm{molecular}<mspace\; width="1em"></mspace>\mathrm{weight}}{5}$

3. $\frac{\mathrm{molecular}<mspace\; width="1em"></mspace>\mathrm{weight}}{2}$

4. $\frac{\mathrm{molecular}<mspace\; width="1em"></mspace>\mathrm{weight}}{10}$

0.1 Mole of ${\mathrm{H}}_3{\mathrm{PO}}_{\mathrm{x}}$ is completely neutralised by 5.6 g KOH then thr true statement is :

1. x = 3 and given acid is dibasic

2. x = 4 and given acid has not P-H linkage

3. x = 2 and given acid does not form acid salt

4. All of these

Balance the following reaction and find the values of a, b and g, respectively

\(aKMnO_4 + bH_2O_2 + 3H_2SO_4 \rightarrow \)
\( dMnSO_4 + eK_2SO_4 + fO_2 + gH_2O\)

1. 2, 4, 8

2. 2, 5, 8

3. 10, 4, 16

4. 8, 5, 2

In the following redox reaction, 

${\mathrm{xFe}}^{2+}+{\mathrm{yCr}}_2{\mathrm{O}}_7^{2-}+14{\mathrm{H}}^{+}\to 6{\mathrm{Fe}}^{3+}+2{\mathrm{Cr}}^{3+}+{\mathrm{zH}}_2\mathrm{O}$

The value of x,y,z are :

1. x = 6, y = 1, z = 7

2. x = 3, y = 6, z = 8

3. x = 6, y = 2, z = 7

4. x = 4, y = 6, z = 7

Balance the following equation and choose the quantity that is the sum of the coefficients of reactants and products :

$...{\mathrm{PtCl}}_4+...{\mathrm{XeF}}_2\to {\mathrm{PtF}}_6+....\mathrm{ClF}+...\mathrm{Xe}$

1. 16

2. 13

3. 18

4. 12

The sum of the coefficients of the reactants in the following reaction is :

$....{\mathrm{CS}}_2+.....{\mathrm{Cl}}_2\to {\mathrm{CCl}}_4+....{\mathrm{S}}_2{\mathrm{Cl}}_2$

1. 5

2. 3

3. 6

4. 4