Q. No.Which one is not a hereditary disease
1. Cystic fibrosis
2. Cretinism
3. Thalassaemia
4. Haemophilia
1. Cystic fibrosis
2. Cretinism
3. Thalassaemia
4. Haemophilia
A woman with normal vision but with colorblind father marries a colorblind man. The fourth child of the couple is a boy. This boy
1. May or may not be colorblind
2. Must be colorblind
3. Must have normal vision
4. Will be partially colorblind due to being heterozygous
Phenotype of an organism is the result to
1. Mutations and linkages
2. Genotype and environment interactions
3. Cytoplasmic effects and nutrition
4. Environmental changes and sexual dimorphism.
In Mendel’s experiments with Garden Pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledons (YY) were dominant over green cotyledons (yy). What is the expected phenotype in F2 generation after the crossing of RRYY x rryy?
| 1. | Only wrinkled seeds with green cotyledons |
| 2. | Only wrinkled seeds with yellow cotyledons |
| 3. | Only round seeds with green cotyledons |
| 4. | Round seeds with yellow cotyledons and wrinkled seeds with green cotyledons. |
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Which of the following is the most suitable medium for the culture of Drosophila melanogaster?
| 1. | Cow dung | 2. | Moist bread |
| 3. | Agar agar | 4. | Ripe Banana |
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Cri-du-chat syndrome in humans is caused by
1. Trisomy of 21st chromosome
2. Loss of half of short arm of chromosome 5
3. Loss of half of long arm of chromosome 5
4. Fertilization of an XX egg by a normal Y- bearing sperm.
Both sickle cell anaemia and Huntington’s chorea are
1. Virus related diseases
2. Bacteria related diseases
3. Congenital disorders
4. Pollution induced disorders
R and Y genes of Maize lie very close to each other. When RRYY and rryy genotype are hybridised, F2 generation will show
1. Segregation in 9: 3 : 3 : 1 ratio
2. Segregation is 3 : 1 ratio
3. Higher number of parental types
4. Higher number of recombinant types
Telomeres with repetitive DNA sequences
1. Act as replicons
2. Are transcription initiators
3. Help in chromosome pairing
4. Prevent chromosome loss.
Test cross involves
1. Crossing between two genotypes with dominant trait
2. Crossing between two genotypes with recessive trait
3. Crossing the F1 hybrid with double recessive genotype
4. Crossing between two F1 hybrids.
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