For a reaction A(s) + 2B+  A2+ + 2B(s) ;  KC has been found to be 1012. The Ecell° is : 

1. 0.35 V 2. 0.71 V
3. 0.01 V 4. 1.36 V

Subtopic:  Relation between Emf, G, Kc & pH |
 76%
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The half cell reduction potential of a hydrogen electrode at pH = 10 will be :

1. 0.59 V                   

2. – 0.59 V

3. 0.059 V                 

4. – 0.059 V

Subtopic:  Nernst Equation |
 69%
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Calculate the Emf of the given cell: 

Zn(s) | Zn+2 (0.1M) || Sn+2 (0.001M) | Sn(s)

(Given EZn+2/Zno=-0.76 V, ESn2+/Sno=-0.14 V)

1. 0.62 V

2. 0.56 V

3. 1.12 V

4. 0.31 V

Subtopic:  Electrode & Electrode Potential |
 56%
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For a cell involving one electron Ecell=0.59 V at 298 K.
The equilibrium constant for the cell reaction is :
Given that 2.303 RTF=0.059 V at T=298 K)

1. 1.0×1030

2. 1.0×102

3. 1.0×105

4. 1.0×1010

Subtopic:  Relation between Emf, G, Kc & pH |
 70%
From NCERT
NEET - 2019
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For the cell reaction \(2Fe^{3+}(aq) \ + \ 2I^{-}(aq)\rightarrow 2Fe^{2+}(aq) \ + \ I_{2}(aq)\)

\(E_{cell}^{o} \ = \ 0.24 \ V\) at 298 K. The standard Gibbs energy ∆rG of the cell reaction is:

[Given: 96500 C mol-1]

1. 23.16 kJ mol-1

2. -46.32 kJ mol-1

3. -23.16 kJ mol-1

4. 46.32 kJ mol-1

Subtopic:  Relation between Emf, G, Kc & pH |
 74%
From NCERT
NEET - 2019
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The potential of a hydrogen electrode having a pH = 10 is : 

1. 0.59 V

2. –0.59 V

3.  0.0 V

4. –5.9 V

Subtopic:  Nernst Equation |
 68%
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If EFe2+/Feo = -0.441 V and  EFe3+/Fe2+o = 0.771 V, the standard emf of the reaction: 

Fe + 2Fe3+→ 3Fe2+ will be:

1. 0.330 V 2. 1.653 V
3. 1.212 V 4. 0.111 V
Subtopic:  Electrode & Electrode Potential |
 71%
From NCERT
AIPMT - 2006
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In producing chlorine through electrolysis, 100 W power at 125 V is being consumed.
The liberation of chlorine per min is:
(ECE of chlorine is 0.367×10-6 kg/C)
1. 17.6 mg 2. 21.3 mg
3. 24.3 mg 4. 13.6 mg
Subtopic:  Faraday’s Law of Electrolysis |
 64%
From NCERT
AIPMT - 2006
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The efficiency of a fuel cell is given by:

1. HG

2. GS

3. GH

4. SG

Subtopic:  Batteries & Salt Bridge |
 64%
AIPMT - 2007
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A steady current of 1.5 A flows through a copper voltmeter for 10 min. If the electrochemical equivalent of copper is 30 × 10-5 g C-1, the mass of copper deposited on the electrode will be:

1. 0.40 g

2. 0.50 g

3. 0.67 g

4. 0.27 g

Subtopic:  Faraday’s Law of Electrolysis |
 76%
From NCERT
AIPMT - 2007
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