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NEET Course - Complete Syllabus
Physics
Thermodynamics
Thermodynamics
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Videos (55)
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#1 | Basic Terms of Thermodynamics
17m 59s
#2 | Zeroth Law
04m 13s
#3 | Thermodynamic Processes
08m 08s
#4 | Isobaric Process
10m 02s
#5 | Isochoric & Isothermal Process
25m 13s
#6 | Interconversion of Graphs
07m 48s
#7 | Solved Example: 1
06m 41s
#8 | Solved Example: 2
06m 43s
#9 | Adiabatic Process
09m 54s
#10 | Solved Example: 3
06m 11s
#11 | Graphs in Adiabatic Process: 1
06m 41s
#12 | Graphs in Adiabatic Process: 2
06m 16s
#13 | Solved Example: 4
01m 18s
#14 | Density Graph
05m 38s
#15 | Polytropic Process
05m 34s
#16 | Internal Energy (U) of Gas
08m 35s
#17 | Solved Example: 5
08m 26s
#18 | Solved Example: 6
09m 15s
#19 | Work (W) done by the Gas: 1
13m 33s
#20 | Solved Example: 7
08m 11s
#21 | Work (W) done by the Gas: 2
07m 05s
#22 | Solved Example: 8
08m 35s
#23 | Solved Example: 9
05m 35s
#24 | Work (W) done by the Gas: 3
02m 02s
#25 | Graphical Intrepretation of Work done
09m 45s
#26 | Solved Example: 10
03m 29s
#27 | Solved Example: 11
08m 19s
#28 | Solved Example: 12
15m 13s
#29 | Work done in Cyclic Process
07m 59s
#30 | Solved Example: 13
06m 05s
#31 | First Law
13m 29s
#32 | Application of First Law to Adiabatic Process
13m 41s
#33 | Application of First Law to Iso Thermal Process
02m 56s
#34 | Solved Example: 14
03m 49s
#35 | Application of First Law to Isochoric & Cyclic Processes
04m 50s
#36 | Solved Example: 15
03m 43s
#37 | Differential Form of First Law
13m 42s
#38| Solved Example: 16
14m 05s
#39 | Solved Example: 17
09m 18s
#40 | Solved Example: 18
09m 31s
#41 | Molar Specific Heat of Gases (C)
07m 31s
#42 | C for Different Processes
20m 05s
#43 | Solved Example: 19
08m 31s
#44 | Solved Example: 20
03m 05s
#45 | Solved Example: 21
03m 35s
#46 | Solved Example: 22
08m 44s
#47 | C for Polytropic Process
15m 25s
#48 | Introduction to Heat Engine
13m 38s
#49 | Solved Example: 23
15m 04s
#50 | Refrigerator
12m 46s
#51 | 2nd Law
07m 13s
#52 | Carnot Engine
15m 38s
#53 | Carnot Cycle
18m 42s
#54 | Solved Example: 24
19m 27s
#55 | Solved Example: 25
12m 18s
Questions
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Doubts (31)
EXPLANATION IS GIVEN THAT ANSWER 2 IS CORRECT BUT .... ANSWER IS MARKED AS 3... PLEASE CHECK
Fri Feb 15 2019
How answer is WORK DONE...?
Fri Feb 15 2019
Answer given is zero degree but in solution its showing temp must be greater than 50 degree...
Thu Feb 14 2019
As efficiency of carnot engine is = 1-T²/T¹ then here 400 =T 1 nd 800 =T2 den how in solution its given 1-400/800...i couldn't understand..
Thu Feb 14 2019
this is correct explanation
Tue Feb 12 2019
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Notes (6)
Error : #18 at 03:14
#19 - Errata - Calculation Error
Errata (Time: 00:57) - #18 - Solved Problems: Set 4
Errata (2 min 22 seconds): #18 | Solved Problems: Set 4
Errata (3 min 10 seconds): #18 | Solved Problems: Set 4
Thermodynamics - NCERT Chapter (PDF)