The intensity at the maximum in Young's double-slit experiment is ${\mathrm{I}}_0$ when the distance between two slits is d=5$\lambda$, where $\lambda$ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D= 10 d?

1. $\frac{{\mathrm{I}}_0}{4}$               

2. $\frac{3}{4}{\mathrm{I}}_0$

3. $\frac{{\mathrm{I}}_0}{2}$             

4. ${\mathrm{I}}_0$

In the Young's double-slit experiment, the intensity of light at a point on the screen (where the path difference is λ ) is K where λ being the wavelength of light used. The intensity at a point where the path difference is λ /4 will be 

1. K
 

2. K/4
 

3. K/2
 

4. zero

In Young’s double slit experiment. the slits are 2 mm apart and are illuminated by photons of two wavelengths , λ₁= 12000Å and , λ₂= 10000Å. At what minimum distance from the common central bright fringe on the screen 2m from the slit will a bright fringe from one interference pattern coincide with a bright fringe from the other?

1. 8mm

2. 6mm

3. 4 mm

4. 3mm

In a double slit experiment, the distance between the slits is \(3\text{ mm}\) and the slits are \(2\text{ m}\) away from the screen one due to light with wavelength \(480\text{ nm},\) and the other due to light with wavelength \(600\text{ nm}.\) What is the separation on the screen between the fifth order bright fringes of the two interference patterns ?
1. \(4\times10^{-4}\text{ m}\)
2. \(9\times10^{-4}\text{ m}\)
3. \(3\times10^{-4}\text{ m}\)
4. \(5\times10^{-4}\text{ m}\)