If a resistance R₂ is connected in parallel with the resistance R in the circuit shown, then possible value of current through R and the possible value of R₂ will be

1. $\frac{I}{3},R$

2. $I,2R$

3. $\frac{I}{3},R$

4. $\frac{I}{2},R$

A battery of emf \(10\) V is connected to resistance as shown in the figure below. The potential difference \(V_{A} - V_{B}\)
between the points \(A\) and \(B\) is:

1. \(-2\) V

2. \(2\) V

3. \(5\) V

4. \(\frac{20}{11}~\text{V}\)

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be 

1. 19 Ω

2. 17 Ω

3. 10 Ω

4. 12 Ω

In the circuit shown below, The reading of the voltmeter V is 

1. 12 V

2. 8 V

3. 20 V

4. 16 V

In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to \(3\) volt. The voltage across the resistance \(R_4\) is:

1. \(0.4\) V
2. \(0.6\) V
3. \(1.2\) V
4. \(1.5\) V