A battery has emf \(4\) V and internal resistance \(r\). When this battery is connected to an external resistance of \(2\) ohm, a current of \(1\) ampere flows in the circuit. How much current will flow if the terminals of the battery are connected directly?
1.
\(1\) A
2.
\(2\) A
3.
\(4\) A
4.
Infinite
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In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference is :
1. 6 V
2. 4 V
3. 2 V
4. –2 V
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PMT - 1997
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In the circuit, the potential difference across PQ will be nearest to
1. 9.6 V
2. 6.6 V
3. 4.8 V
4. 3.2 V
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The e.m.f. of a cell is E volts and internal resistance is rohm. The resistance in external circuit is also rohm. The p.d. across the cell will be
1. E/2
2. 2E
3. 4E
4. E/4
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Level 1: 80%+
PMT - 1985
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The terminal potential difference of a cell when short-circuited is (E = E.M.F. of the cell)
1. E
2. E/2
3. Zero
4. E/3
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