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Related Practice Questions :

A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

(1)     ±A          

(2)    Zero

(3)     ±A2         

(4)   ±A2

 80%
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The potential energy of a particle with displacement X depends as U(X). The motion is simple harmonic, when (K is a positive constant)

(1) U=KX22                 

(2) U=KX2   

(3)  U=K                       

(4) U=KX 

 81%
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The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is 

(1)     X2ω2a2-X2ω2       

(2)    X2/a2-x2

(3)   a2-X2ω2/X2ω2       

(4)   (a2-x2)/X2

 78%
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A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy, will be:

1.   f/2         

2.  f

3.   2 f        

4.  4 f

 60%
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There is a body having mass m and performing S.H.M. with amplitude a. There is a restoring force ,F=-Kx where x is the displacement. The total energy of body depends upon -

(1)   K, x         

(2)  K, a

(3)   K, a, x    

(4)  K, a, v

 71%
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