I
15.03 cm3 CH4(NTP) is dissolved in 500 cm3 water.
Thus, we have Volume v dissolved in 1 cm3 water = 15.30500×1=0.03006cm3
Amount of gas dissolved = PVRT=1×0.0300682.06×273
=1.34 X 10-6mol
Mass of gas disolved, m=1.34 X 10-6 X 16 = 2.144 X 10-5gm
Now, according to Henry's law, we have m=Kp (K- Henry constant. K=m/p.
Substituting the values of m and p, we get K=2.144 X 105gm atm-1
Now for 1 X 10-3mole of gas in 300cm-3 of water we have Mass of gas dissolved in 1 cm3 water
=1×10-3×16300×1=5.33×10-5gm
From Henry's law, pressure required to dissolve the above amount =