Doubt by Atul Mishra

25g ethylene glycol is present in 100g of water the solution cooled -10c. kf for water 1.86k kgper mol. the amount of ice seprated on cooling is

Answers

Answer by Rishikant Pandey

Molal depression constant = Depression in Kelvin per mole of solute present in kg of solvent.

molecular mass of Ethylene Glycol = C2 H6 O2 = 62 gm/mole
Number of moles/kg of water = 25 /62 * 1000/100 = 4.03 moles/kg
Actual depression in freezing point temperature: 1.86 °K * 4.03 = 7.49°K

Specific heat of Ice = 2 J/gm-°K
Heat released from 200gm of water(ice) due to lowering of temperature
  = 7.49 * 2 * 100 = 1498 J
Latent heat of fusion of ice = 334 kJ /kg = 334 J/gm

Amount of ice that will melt away due to availability of 2, 976 J:
     = 1498/334
     = 4.49 gm

Answer by Rishikant Pandey

PLEASE CORRECT

Heat released from 100gm of water(ice) due to lowering of temperature=7.49*2*100=1498 J