Question 19 of 155

In Rutherford's alpha scattering experiment using gold foil, the kinetic energy of the alpha particle was 1.2 x 10^-12J. For a head on collision, using the formula K.E. = $\frac{1}{4{\mathrm{\pi \epsilon }}_0}$x 2Ze²/r₀ , what may be the magnitude of r₀ [ The nuclear radius of gold, Z=79; $\frac{1}{4{\mathrm{\pi \epsilon }}_0}$= 9 x 10⁹ new-ton/meter² coulomb^-2, e= 1.6x10^-19 coulomb]

1. 3 x 10^-14m

2. 1.3 x 10^-14m

3. 2.1 x 10^-14m

4. 4.3 x 10^-14m