Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be (Take specific heat of water=1 cal g-1 °C-1 and latent heat of steam = 540 cal g-1)
(a) 24 g
(b) 31.5g
(c) 42.5 g
(d) 22.5 g