Doubt by Divya devangada

It can be dolike  this . then answer is different.this method right or wrong

 

Answers

Answer by nitesh chaudhary

If you read the question carefully, the equivalent conductivity of Ba2+BaX2+ and Cl1ClX−1 are provided to you.

So the molar conductivity of Ba2+BaX2+ is: 2×127 ohm1mole1=254 

and that of Cl1=76 

Now apply Kohlrausch's law of molar conductivity of solution at infinite dilution:

𝜆𝑜BaCl2=𝜆𝑜Ba2++2𝜆𝑜Cl1𝜆𝑜BaCl2=254+2×76=406 Now, , equivalent conductivity is 1/2 times the molar conductivity for BaCl2BaClX2 so equivalent conductivity of BaCl2=1/2×406=203