Kirchhoff's first law i.e. $\Sigma i=0$ at a junction is based on the law of conservation of :

(1) Charge

(2) Energy

(3) Momentum

(4) Angular momentum

The figure below shows currents in a part of electric circuit. The current i is

(1) 1.7 amp

(2) 3.7 amp

(3) 1.3 amp

(4) 1 amp

The figure shows a network of currents. The magnitude of currents is shown here. The current i will be 

(1) 3 A

(2) 13 A

(3) 23 A

(4) – 3 A

The current in the arm CD of the circuit will be:
           
1. $i_1+i_2$

2. $i_2+i_3$

3. $i_1+i_3$

4. $i_1-i_2+i_3$

Kirchhoff’s first and second laws for electrical circuits are consequences of:

Current through the branch AO is- 

1.  2 A

2.  4 A

3.  1 A

4.  Zero

The value of electric current i₁ in the network below is 

1  5 A

2  9 A

3  8 A

4  7 A

In the network shown, the potential at junction D is

1  $\frac{180}{11}V$

2  $\frac{11}{180}V$

3  10 V

4  5 V 

The current I in the circuit shown below is:

1. $-3 \mathrm{A}$

2. 3 A

3. 13 A

4. 20 A

As the switch is closed in the circuit then current passed through it is 

1  7.5 A

2  3 A

3  4.5 A

4  Zero