NEET Questions Solved

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NEET - 2015

Figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be-


(a) 380 J 
(b) 500 J
(c) 460 J
(d) 300 J

Since, initial and final points are same
                         

So, UABC = UAC                                                ........iAlso AB is isochoric processSo   WAB=0and   Q=U+WSo,   QAB=UAB=400 JNext  BC is isobaric process.So,   QBC=UBC+WBC                       = UBC+PVBC     100=UBC+6×104 2×10-3      UBC=100-120 =-20 JFrom Equation (i):       UABC=UAC UAB+UBC = QAC-WAC 400+-20=QAC-Area under AC QAC=380+2×104×2×10-3+12×2×10-3×4×104                   =380+40+40    QAC=460 J

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NEET - 2012

A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is 

(a)2 pV                                     (b)4 pV

(c)12pV                                    (d)pV

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NEET - 2012

An ideal gas goes from state A to state B

via three different processes as indicated 

in the p-V diagram

If Q1, Q2, Q3 indicates the heat absorbed

by the gas along the three processes and 

U1, U2, U3 indicates the change in 

internal energy along the three processes

respectively, then

(a) Q1>Q2>Q3 and U1= U2= U3

(b) Q3>Q2>Q1 and U1= U2= U3

(c) Q1=Q2=Q3 and U1>U2>U3

(d) Q3>Q2>Q1 and U1>U2>U3

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NEET - 2009

The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is 

(a) 8900 J                                      (b) 6400 J

(c) 5400 J                                      (d) 7900 J

Heat given to a system (Q) is equal to the sum of increase in the internal energy u and the work done W by the system against the surrounding and 1 cal=4.2J.

According to first law of thermodynamics

            U=Q-W

                 = 2×4.2×1000-500

                = 8400-500

                = 7900 J

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A system performs work ΔW when an amount of heat is ΔQ added to the system, the corresponding change in the internal energy is ΔU. A unique function of the initial and final states (irrespective of the mode of change) is -

(1) ΔQ

(2) ΔW

(3) ΔU and ΔQ

(4) ΔU

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A container of volume 1m3 is divided into two equal compartments by a partition. One of these compartments contains an ideal gas at 300 K. The other compartment is vaccum. The whole system is thermally isolated from its surroundings. The partition is removed and the gas expands to occupy the whole volume of the container. Its temperature now would be -

(1) 300 K

(2) 239 K

(3) 200 K

(4) 100 K

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110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is 

(1) 150 J

(2) 70 J

(3) 110 J

(4) 40 J

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When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is -

(1) 166 cal

(2) 333 cal

(3) 500 cal

(4) 400 cal

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