# NEET Questions Solved

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)
NEET - 2017

Thermodynamic process are indicated in the following diagram

Match the following:

column-I            column-II

Q.       Process-II      (b)   Isobaric

R.       Process-III     (c)   Isochoric

S.       Process-IV     (d)   Isothermal

(a) $P\to a,Q\to c,R\to d,S\to b$

(b)$P\to c,Q\to a,R\to d,S\to b$

(c)$P\to c,Q\to d,R\to b,S\to a$

(d)$P\to c,Q\to d,R\to b,S\to a$

(b)In isochoric process, the curve is parallel to y-axis because volume is constant. Isobaric is parallel to x-axis because pressure is constant. Along the curve, it will be isothermal because temperature is constant.

So,     $P\to c\phantom{\rule{0ex}{0ex}}Q\to a\phantom{\rule{0ex}{0ex}}R\to d\phantom{\rule{0ex}{0ex}}S\to b$

Difficulty Level:

• 12%
• 72%
• 15%
• 3%
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NEET - 2012

One mole of an ideal gas from an initial state B undergoes via two processes. It first undergoes isothermal expansion from volume V to 3V and then its volume is reduced from 3V to V at constant pressure. The correct p-V diagram representing the two processes is -

According to question first gas goes from volume V to 3V and after this volume is reduced from 3V to V at constant pressure. In isothermal expansion p-V curve is rectangular hyperbola.

Option (d) is correct

Difficulty Level:

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• 12%
• 36%
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NEET - 2011

A mass of diatomic gas ($\gamma$=1.4) at a pressure of 2 atm is compressed adiabatically so that its temperature rise from $27°\mathrm{C}$ to $927°\mathrm{C}.$ The pressure of the gas is final state is

(a) 28 atm                                            (b) 68.7 atm

(c) 256 atm                                           (d) 8 atm

${\mathrm{pV}}^{\mathrm{\gamma }}=$constant