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PV=k                    ........Isothermal ProcessVdP + pdV =0        dPPIsothermal=-dVV         PVγ=k         VγdP + γPVγ-1 dV=0                ........ Adiabatic process         dPPAdiabatic=-γdVVdPPAdiabaticdPPIsothermal=γ

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Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)

Crack NEET with Online Course - Free Trial (Offer Valid Till August 28, 2019)
NEET - 2017

Thermodynamic process are indicated in the following diagram 

  Match the following:

             column-I            column-II

P.        Process-I      (a)    Adiabatic

Q.       Process-II      (b)   Isobaric 

R.       Process-III     (c)   Isochoric

S.       Process-IV     (d)   Isothermal

 

(a) Pa,Qc,Rd,Sb

(b)Pc,Qa,Rd,Sb

(c)Pc,Qd,Rb,Sa

(d)Pc,Qd,Rb,Sa

(b)In isochoric process, the curve is parallel to y-axis because volume is constant. Isobaric is parallel to x-axis because pressure is constant. Along the curve, it will be isothermal because temperature is constant. 

 So,     PcQaRdSb

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NEET - 2012

 

One mole of an ideal gas from an initial state B undergoes via two processes. It first undergoes isothermal expansion from volume V to 3V and then its volume is reduced from 3V to V at constant pressure. The correct p-V diagram representing the two processes is -

 

According to question first gas goes from volume V to 3V and after this volume is reduced from 3V to V at constant pressure. In isothermal expansion p-V curve is rectangular hyperbola.

Option (d) is correct

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NEET - 2011

A mass of diatomic gas (γ=1.4) at a pressure of 2 atm is compressed adiabatically so that its temperature rise from 27°C to 927°C. The pressure of the gas is final state is 

(a) 28 atm                                            (b) 68.7 atm

(c) 256 atm                                           (d) 8 atm

T1=273+27=300 kT2=273+927=1200 k 

Gas equation for adiabatic process

         pVγ=constant 

            PTPγγ-1= constant               (pV=RT)        P2P1=T2T1γγ-10r          P2=P1T2T1γγ-1              P2=212003001.41.4-1              P2=256 atm

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