An absorption line of the lowest frequency in the transition of hydrogen spectra is

1. n=1 to n=2

2. n=3 to n=8

3. n=2 to n=1

4. n=8 to n=3

The first line in the Lyman series in the spectrum of hydrogen atom occurs at a wavelength of 1215 Å and the limit for Balmer series is 3645 Å. Calculate the wavelength corresponding to series limit of Lyman series.

1. 911.2 Å

2. 812.2 Å

3. 712.2 Å

4. 678.4 Å

With a certain exciting radiation of a particular frequency, to which hydrogen atoms are exposed, the maximum number of spectral lines obtainable in the emission is 15. The uppermost energy level to which the electron is excited is 

1. 4

2. 5

3. 6

4. 7

The brackett series of spectral lines arise when an electron in an excited hydrogen atom jumps from an energy level

1. n=5 to n=1

2. n=5 to n=3

3. n=5 to n=4

4. n=5 to n=2

The electronic transition in the hydrogen atom that emits maximum energy is:

1. 2 $\to$ 1

2. 1 $\to$ 4

3. 4 $\to$ 3

4. 3 $\to$ 2

The spectrum of He-atom may be considered similar to the spectrum of - 

1. H

2. Li⁺

3. Na

4. He⁺

The mass ratio of photons corresponding to the first lines of the Lymann and the Balmer series of the atomic spectrum of hydrogen is :

For the energy levels in an atom, which one of the following statements is correct -

1. There are seven principal electron energy levels

2. The second principal energy level can have two 'sub energy levels and contains a maximum of eight electrons

3. The energy level can have a maximum of 32 electrons

4. The 4s sub-energy level is at higher energy than the 3d sub-energy level

The wavelength of the photoelectric threshold of metal is 230 nm. Determine the K.E. of photoelectron ejected from the surface by UV radiation emitted from the second-longest wavelength transition (downward) of an electron in Lyman series of the atomic spectrum of hydrogen. (R=1.09677 x 107 m^-1)

1. 1.074 x 10^-18 J

2. 1.937 x 10^-18J

3. 6.213 × 10^-18 J

4. 7.123 x 10^-10J

What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition, n=4 to n=2 in the He⁺ spectrum?

1. n =4 to n=2

2.  n = 3 to n=2

3.  n =3 to n=1

4.  n =2 to n=1