A spring 40 mm long is stretched by the application of a force. If 10 N force required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is

(a) 84J

(b) 68J

(c) 23J

(d) 8J

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#6 | Solved Problems on Potential Energy
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Elastic potential energy
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#6 | Solved Problems on Potential Energy
#7 | Mechanical Energy

Concept Questions :-

Elastic potential energy
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Concept Videos :-

#6 | Solved Problems on Potential Energy
#7 | Mechanical Energy

Concept Questions :-

Elastic potential energy
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Concept Videos :-

#6 | Solved Problems on Potential Energy
#7 | Mechanical Energy

Concept Questions :-

Elastic potential energy
Explanation is a part of a Paid Course. To view Explanation Please buy the course.

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Concept Videos :-

#6 | Solved Problems on Potential Energy
#7 | Mechanical Energy

Concept Questions :-

Elastic potential energy
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Which of the following graph depicts spring constant k versus length l of the spring correctly

(1)
(2)
(3)
(4)

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#6 | Solved Problems on Potential Energy
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Concept Questions :-

Elastic potential energy
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Two springs have their force constant as k1 and k2(k1>k2). When they are stretched by the same force 

(1) No work is done in case of both the springs

(2) Equal work is done in case of both the springs

(3) More work is done in case of second spring

(4) More work is done in case of first spring

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#6 | Solved Problems on Potential Energy
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Concept Questions :-

Elastic potential energy
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The potential energy of a certain spring when stretched through a distance ‘S’ is 10 joule. The amount of work (in joule) that must be done on this spring to stretch it through an additional distance ‘S’ will be:

(1) 30

(2) 40

(3) 10

(4) 20

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#6 | Solved Problems on Potential Energy
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Concept Questions :-

Elastic potential energy
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A spring of force constant 800 N/m has an extension of 5cm. The work done in extending it from 5cm to 15 cm is:

(1) 16 J

(2) 8 J

(3) 32 J

(4) 24 J

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#6 | Solved Problems on Potential Energy
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Elastic potential energy
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A spring of spring constant 5 × 103 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is 

(1) 6.25 N-m

(2) 12.50 N-m

(3) 18.75 N-m

(4) 25.00 N-m

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#6 | Solved Problems on Potential Energy
#7 | Mechanical Energy

Concept Questions :-

Elastic potential energy
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