A particle is moving with veocity v=k(yi^+xj^); where k is constant. The general equation for the path is:

1. y=x2+constant

2. y2=x2+constant

3. y=x+constant

4. xy=constant

 

Subtopic:  Speed & Velocity |
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In \(1.0\) s, a particle goes from point A to point B, moving in a semicircle of radius \(1.0\) m (see figure). The magnitude of the average velocity is:

   
1. \(3.14\) m/s
2. \(2.0\) m/s
3. \(1.0\) m/s
4. zero

Subtopic:  Speed & Velocity |
 69%
From NCERT
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The coordinates of a moving particle at any time ‘t’ are given by x = αt3 and y = βt3. The speed of the particle at time ‘t’ is given by:

1. α2+β2

2. 3 tα2+β2

3. 3 t2α2+β2

4. t2α2+β2

Subtopic:  Speed & Velocity |
 78%
From NCERT
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A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t = 0, (6m, 7m) at time t = 2s and (13m, 14m) at time t = 5s. Average velocity vector (vav) from t = 0 to t = 5s is

1. 15(13i^+14j^)

2. 73(i^+j^)

3. 2(i^+j^)

4. 115(i^+j^)

Subtopic:  Speed & Velocity |
 79%
From NCERT
NEET - 2014
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The coordinates of a moving particle at a time t, are given by, x = 5sin10t, y = 5cos10t. The speed of the particle is:

(1)  25

(2)  50

(3)  10

(4)  502

Subtopic:  Speed & Velocity |
From NCERT
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A car turns at a constant speed on a circular track of radius \(100\) m, taking \(62.8\) s for every circular lap. The average velocity and average speed for each circular lap, respectively, is:

1. \(0,~0\) 2. \(0,~10\) m/s
3. \(10\) m/s, \(10\) m/s 4. \(10\) m/s, \(0\)

Subtopic:  Speed & Velocity |
 82%
From NCERT
AIPMT - 2006
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If three coordinates of a particle change according to the equations x=3t2, y=2t, z=4, then the magnitude of the velocity of the particle at time \(t=1\) second will be:
1. 211 unit 

2. 34 unit

3. \(40\) unit

4. 210 unit

Subtopic:  Speed & Velocity |
 80%
From NCERT
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Two particles move from A to C and A to D on a circle of radius R and diameter AB. If the time taken by both particles are the same, then the ratio of magnitudes of their average velocities is:
                                
1. 2

2.  23

3.  3

4.  32

Subtopic:  Speed & Velocity |
 62%
From NCERT
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A particle moves on the curve \(x^2 = 2y\). The angle of its velocity vector with the x-axis at the point \(\left(1, \frac{1}{2}\right )\) will be:

1. \(30^\circ\) 2. \(60^\circ\)
3. \(45^\circ\) 4. \(75^\circ\)
Subtopic:  Speed & Velocity |
 61%
From NCERT
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A particle starts moving from the origin in the XY plane and its velocity after time \(t\) is given by \(\overrightarrow{\mathrm{v}}=4 \hat{\mathrm{i}}+2 \mathrm{t} \hat{\mathrm{j}}\). The trajectory of the particle is correctly shown in the figure:

1. 2.
3. 4.


 

Subtopic:  Speed & Velocity |
 60%
From NCERT
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