What is the number of significant figures in \(0.310\times 10^{3}\)?
1. \(2\)
2. \(3\)
3. \(4\)
4. \(6\)
The decimal equivalent of \(\frac{1}{20} \) up to three significant figures is:
1. | \(0.0500\) | 2. | \(0.05000\) |
3. | \(0.0050\) | 4. | \(5.0 \times 10^{-2}\) |
If L = 2.331 cm, B = 2.1 cm, then L + B =?
1. 4.431 cm
2. 4.43 cm
3. 4.4 cm
4. 4 cm
If \(97.52\) is divided by \(2.54\), the correct result in terms of significant figures is:
1. | \( 38.4 \) | 2. | \(38.3937 \) |
3. | \( 38.394 \) | 4. | \(38.39\) |
Assertion : Number of significant figures in 0.005 is one and that in 0.500 is three.
Reason : This is because zeros are not significant.
Assertion: Out of three measurements l = 0.7 m; l = 0.70 m and l = 0.700 m, the last one is most accurate.
Reason: In every measurement, only the last significant digit is not accurately known.
The length, breadth, and thickness of a block are given by l = 12 cm, b = 6 cm and t = 2.45 cm The volume of the block according to the idea of significant figures should be:
(1) 1 × 102 cm3
(2) 2 × 102 cm3
(3) 1.764 × 102 cm3
(4) None of these
Taking into account the significant figures, what is the value of \((9.99~\mathrm{m}-0.0099~\mathrm{m})\)?
1. | \(9.98\) m | 2. | \(9.980\) m |
3. | \(9.9\) m | 4. | \(9.9801\) m |
The number of significant figures in \(0.0006032\) m2 is:
1. | 4 | 2. | 5 |
3. | 7 | 4. | 3 |
The length, breadth, and thickness of a rectangular sheet of metal are \(4.234\) m, \(1.005\) m, and \(2.01\) cm respectively. The volume of the sheet to correct significant figures is:
1. \(0.00856\) m3
2. \(0.0856\) m3
3. \(0.00855\) m3
4. \(0.0855\) m3