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The hydrated salt, Na2SO4.nH2O, undergoes a 55% loss in mass on heating and becomes anhydrous. The value of n will be:

1. 5 2. 3
3. 7 4. 10
Subtopic:  Empirical & Molecular Formula |
 54%
Level 3: 35%-60%
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A metal M forms a compound M2HPO4. The formula of the metal sulphate is:

1. M2SO4 

2. MSO4

3. M(SO4)2

4. M2(SO4)3

Subtopic:  Empirical & Molecular Formula |
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Level 2: 60%+
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The empirical formula of an organic compound containing carbon and hydrogen is CH2. The mass of one litre of this organic gas at STP  is exactly equal to that of one litre of N2 at STP. Therefore, the molecular formula of the organic gas is:

1. C2H4

2. C3H6

3. C6H12

4. C4H8

Subtopic:  Moles, Atoms & Electrons | Empirical & Molecular Formula |
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A sample of pure compound is found to have Na = 0.0887 mole, O = 0.132 mole, C = 2.65 × 1022 atoms.

The empirical formula of the compound is 

(1) Na2CO3

(2) Na3O2C5

(3) Na0.088700.132C2.65×1022

(4) NaCO

Subtopic:  Empirical & Molecular Formula |
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An organic compound containing C, H, and N gave the following on analysis: C = 40%, H = 13.3% and N = 46.67%. Its empirical formula would be:

1. CHN
2. C2H2N
3. CH4N
4. C2H7N

Subtopic:  Empirical & Molecular Formula |
 82%
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An organic substance containing C, H, and O gave the following percentage composition :

C = 40.687%, H = 5.085% and O = 54.228%. The vapour density of this organic substance is 59.

The molecular formula of the compound will be:

1. C4H6O4

2. C4H6O2

3. C4H4O2

4. None of the above

Subtopic:  Empirical & Molecular Formula |
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Level 2: 60%+
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 If 2.74 g of the metal oxide contains 1.53 g of metal, then the empirical formula of vanadium oxide is:

(Atomic Mass of V = 52)

1. V2O3

2. VO

3. V2O5

4. V2O7

Subtopic:  Empirical & Molecular Formula |
 58%
Level 3: 35%-60%
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A gaseous compound is composed of 85.7% by mass carbon and 14.3% by mass hydrogen. It's density is 2.28 g/litre at 300 K and 1.0 atm pressure. Determine the molecular formula of the compound:

1.  C2H2

2.  C2H4

3.  C4H8

4.  C4H10

Subtopic:  Empirical & Molecular Formula |
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On complete combustion, 44 g of a sample of a compound gives 88 g CO2 and 36 g of H2O. The molecular formula of the compound may be:

1.  C4H6 

2.  C2H6O 

3.  C2H4O

4.  C3H6O

Subtopic:  Empirical & Molecular Formula |
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An oxide of iron contains 69.9% iron and 30.1% oxygen by mass. What is its empirical formula?

1. FeO

2. Fe2O3

3. Fe3O4

4. Fe3O2

Subtopic:  Empirical & Molecular Formula |
 61%
Level 2: 60%+
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