In the following reaction, 

${\mathrm{CH}}_3\mathrm{CHO}+\mathrm{HCN}\to {\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{OH}\right)\mathrm{CN}\stackrel{{\mathrm{H}}^{+}/{\mathrm{H}}_2\mathrm{O}}{\to } {\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{OH}\right)\mathrm{COOH}$

an asymmetric center is generated. The acid obtained would be

1. L-isomer
2. D-isomer
3. 20% D+ 80% L-isomer
4. 50% D+ 50 % L-isomer

The major organic product formed from the following reaction

 $\underset{\left(\mathrm{ii}\right) {\mathrm{LiAlH}}_4 \left(\mathrm{iii}\right) {\mathrm{H}}_2\mathrm{O}}{\overset{\left(\mathrm{i}\right) {\mathrm{CH}}_3{\mathrm{NH}}_2}{\to }}$ ... is

1.                   

2.  

3.                 

4.  

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of $\mathrm{\alpha }$-hydroxy acid. The carbonyl compound is

1. acetaldehyde 

2. acetone

3. diethyl ketone 

4. formaldehyde                              

 A and B in the following reactions are $\underset{\mathrm{KCN}}{\overset{\mathrm{HCN}/}{\to }}$A$\stackrel{\mathrm{B}}{\to }$

1. A=${\mathrm{RR}}^{\text{'}}{\mathrm{CH}}_2\mathrm{CN}$, B=NaOH

2. A=, B=${\mathrm{CH}}_3$

3. A=, B=${\mathrm{CH}}_3$

4. A=, B=${\mathrm{LiAlH}}_4$

Consider the following reaction,

Phenol$\stackrel{\mathrm{Zn}-\mathrm{dust}}{\to }$X$\underset{\mathrm{Anhy}.{\mathrm{AlCl}}_3}{\overset{{\mathrm{CH}}_3\mathrm{Cl}}{\to }}$Y$\stackrel{\mathrm{Alk}.{\mathrm{KMnO}}_4}{\to }$Z 

The product Z is                            

1. toluene

2. benzaldehyde

3. benzoic acid

4. benzene

The compound formed when malonic acid heated with urea, is                  

1. cinnamic acid

2. butyric acid

3. barbituric acid

4. crotonic acid

Trichloroacetaldehyde, CCl₃CHO reacts with chlorobenzene in the presence of sulphuric acid and produces                                                                         

1. 

2. 

3. 

4. 

What is formed when a primary alcohol undergoes catalytic dehydrogenation?

1. Aldehyde 

2. Ketone 

3. Alkene

4. Acid 

The compound which on reduction with ${\mathrm{LiAlH}}_4$ gives two diffrent alcohols:

1. ${\mathrm{CH}}_3{\mathrm{COOCH}}_3$                         

2.  ${\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5$

3. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$                           

4.  ${\mathrm{CH}}_3\mathrm{CHO}$

Ethyl ester $\underset{\mathrm{Excess}}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$ P. the product P will be: 

1. 

2. 

3.

4.