Chlorobenzene reacts with Mg in dry ether to give a compound (A).
A and ethanol continue to react in order to produce?

Ethyl chloride is converted into diethyl ether by -                                                  

 1. Wurtz reaction                           
 2. Grignard reaction
 3. Perkin's reaction                       
 4. Williamson's synthesis

 , Cl obtained by chlorination of n-butane, will be                

1. meso form              

2. racemic mixture

3. d-form                 

4. l-form

In ${\mathrm{S}}_{{\mathrm{N}}^2}$ reactions, the correct order of reactivity for the following compounds : ${\mathrm{CH}}_3\mathrm{Cl}$, ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$, ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$ and ${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$ is :

1. ${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

2. ${\mathrm{CH}}_3\mathrm{Cl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

4. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

Action of RMgX with vinyl chloride gives:

1. alkane                                 

2. alkyne

3. alkene                                 

4. all of these

What would be the product formed when 1-bromo-3-chlorocyclobutane reacts with two equivalents of metallic sodium in ether?

1.   

2. 

3.    

4. 

Benzyl chloride (C₆H₅CH₂Cl) can be prepared from toluene by chlorination with:

1. SO₂Cl₂

2. SOCl

3. S₂Cl₂

4. NaOCl₂

The nitration of nitrobenzene with fuming HNO₃ will give:

1. TNB

2. 1,3-dinitrobenzene

3. picric acid

4. 1,4-dinitrobenzene

Arrange the following alkyl halides in the decreasing order of ${\mathrm{S}}_{\mathrm{N}}1$ reactivity

(I) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$

(II) ${\mathrm{CH}}_2=\mathrm{CHCH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$

(III) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$

1. I>II>III                            2. II>I>III

3. II>III>I                            4. III>II>I

The correct order of solvolysis in the following alkyl halide is

1.   >  ${\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Cl}$  >  ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$

2.   ${\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Cl}$     >   >  ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$

3.   ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$  >   ${\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Cl}$    >    

4.  ${\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Cl}$  >   ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$   >