In the Haber process, 30 L of dihydrogen and 30 L of dinitrogen were taken for the reaction, which yielded only 50% of the expected product. The composition of the gaseous mixture under the said conditions in the end is: 

1. 20 L ammonia, 10 L nitrogen, 30 L hydrogen

2. 20 L ammonia, 25 L nitrogen, 15 L hydrogen

3. 20 L ammonia, 20 L nitrogen, 20 L hydrogen

4. 10 L ammonia, 25 L nitrogen, 15 L hydrogen

Subtopic:  Limiting Reagent |
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1 gm butane (C4H10) is burnt with excess of O2 to form CO2. The approximate mass of CO2 produced is

1. 1gm

2. 2gm

3. 3gm

4. 4gm

Subtopic:  Limiting Reagent |
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If 0.5 moles of BaCl2 is reacted with 0.2 moles of Na3PO4 then the maximum moles of Ba3(PO4)2 formed is:

1. 0.33 2. 0.25
3. 0.10 4. 0.52
Subtopic:  Limiting Reagent |
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The moles of lead (II) chloride that will be formed from a reaction
between 6.5 g of PbO and 3.2 g of HCl are:

1. 0.044
2. 0.333
3. 0.011
4. 0.029

Subtopic:  Limiting Reagent |
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AIPMT - 2008
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To produce 20 moles of ammonia via Haber's process, how many moles of hydrogen molecules are required?

1. 40 mol 2. 10 mol
3. 20 mol 4. 30 mol
Subtopic:  Limiting Reagent | Equation Based Problem |
 80%
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NEET - 2019
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25.4 g of I2 and 14.2 g  of Cl2 are made to react completely to yield a mixture of ICI and ICI3. The mole of ICI and ICI3 formed, is respectively -

1. 0.5, 0.2

2. 0.1, 0.1

3. 0.1, 0.3

4. 0.3, 0.4

Subtopic:  Limiting Reagent | Equation Based Problem |
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5 mL of a gaseous hydrocarbon was exposed to 30 mL of O2. The resultant gas, on cooling is found to measure 25 mL of which 10 mL is absorbed by NaOH and the remainder by pyrogallol. Determine molecular formula of hydrocarbon. All measurements are made at constant room temperature.

1. CH4

2. C2H2

3. C3H4

4.C2H4

Subtopic:  Limiting Reagent |
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60 mL of a mixture of nitrous oxide and nitric oxide was exploded with excess of hydrogen. If 38 mL of N2 was formed, calculate the volume of each gas in the mixture. All measurements are made at constant P and T.

1.20 ml +30 ml

2. 44 ml + 16 ml

3. 10 ml+40 ml

4 .25 ml +25 ml

Subtopic:  Limiting Reagent |
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ln, a closed vessel, 50 ml of A2B3 completely reacts with 200 ml of C2 according to the following equation:

2A2B3(g) + 5C2(g) 3C3B2(g)+CA4(g)

The composition of the gaseous mixture in the system will be:

1. 100 ml C2, 50 ml C3B2,50 ml CA4

2. 25 ml C2, 75 ml  C3B2, 25 ml CA4

3. 75 ml C2, 75 ml C3B2, 25 ml CA4

4. 10 ml C2, 25 ml C3B2, 100 ml CA4

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If 0.50 mole of BaCl2 is mixed with 0.20 mole of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is -

1. 0.10

2. 0.20

3. 0.30

4. 0.40

Subtopic:  Limiting Reagent |
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