CrO42- (yellow) changes to Cr2O72- (orange) in pH = x and vice versa in pH = y.
The value of x and y will be:
1. 6, and 8
2. 6, and 5
3. 8, and 6
4. 7, and 7
The colour of KMnO4 is due to :
1. d-d transition
2. Charge transfer spectra
3. Polarisation of ion
4. p-d transition
Cr2O72-+XCr3++H2O + oxidized product of X. X in the above reaction cannot be
1. C2O42-
2. Fe2+
3. SO42-
4. S2-
In the dichromate ion Cr2O72-,
1. 4 Cr-O bonds are equivalent
2. 6 Cr-O bonds are equivalent
3. All Cr-O bonds are equivalent
4. None of Cr-O bonds are equivalent
Name the gas that can readily decolourise acidified KMnO4 solution.
(1) CO2
(2) SO2
(3) NO2
(4) P2O5
HgCl2 and I2 both when dissolved in water containing I- ions the pair of species formed is
(a) HgI2, (b) HgI2, I-
(c) (d) Hg2I2, I-
Which one of the following statements is correct when SO2 is passed through acidified
K2Cr2O7 solution?
1. The solution is decolourized
2. SO2 is reduced
3. Green Cr2(SO4)3 is formed
4. The solution turns blue
Which of the statements is not true?
1. On passing H2S through acidified K2Cr2O7 solution, a milky colour is observed
2. Na2Cr2O7 is preferred over K2Cr2O7 in volumteric analysis
3. K2Cr2O7 solution in acidic medium is orange
4. K2Cr2O7 solution becomes yellow on increasing the pH beyond 7
Acidified permanganate solution does not oxidize:
(1)
(2)
(3)
(4)
At
1. Decomposes into
2. Decomposes into
3. Sublimes go give liquid
4. Sublimes to give gaseous dimmer